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posledela
4 years ago
10

The number of customers for a new online business can be modeled by y = 8x2 + 100x + 250, where x represents the number of month

s since the business started. Which is the best prediction for the number of customers in month 20?
Mathematics
1 answer:
kenny6666 [7]4 years ago
3 0
The best prediction for the number of customers is 5450.

To find this value, you just need to plug in 20 for x into the expression. Then, evaluate it using the order of operations.

8(20)^2 + 100(20) + 250
8(400) + 100(20) + 250
3200 + 2000 + 250
5450
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Answer:

\frac{3}{8} or\ 0.375\ km

Step-by-step explanation:

Given: Chandler walk 1/16 km every 10 minutes.

First, lets find how many 10 minutes in one hours or convert minutes in hours.

∴ Time= \frac{60}{10} \ h

Now, finding kilometres travelled in 1 hour.

Distance travelled= \frac{1}{16} \times \frac{60}{10} = \frac{1}{16} \times 6

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Converting \frac{3}{8} \ km into decimal will have 0.375 km.

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7 0
3 years ago
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3 years ago
Use spherical coordinates to find the volume of the region that lies outside the cone z = p x 2 + y 2 but inside the sphere x 2
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I assume the cone has equation z=\sqrt{x^2+y^2} (i.e. the upper half of the infinite cone given by z^2=x^2+y^2). Take

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The volume of the described region (call it R) is

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\sin\varphi=\dfrac1{\sqrt2}\implies\varphi=\dfrac\pi4

(I've added a picture to better demonstrate this)

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\displaystyle2\pi\left(\int_0^{\sqrt2}\rho^2\,\mathrm d\rho\right)\left(\int_{\pi/4}^\pi\sin\varphi\,\mathrm d\varphi\right)=\boxed{\frac43(1+\sqrt2)\pi}

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