D because d is always right hahahahaha
Answer:
sad life
Step-by-step explanation:
The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
We have:
The length of a new rectangle playing field is 6 yards longer than quadruple the width.
Let's suppose the length is l and width is w of a rectangle:
From the problem:
l = 6 + 4w
Perimeter P = 2(l + w)
532 = 2(l + w)
Plug l = 6+4w in the above equation:
532 = 2(6 + 4w + w)
266 = 6 + 5w
260 = 5w
w = 52 yards
l = 6 +4(52) = 214 yards
Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
Learn more about the area of rectangle here:
brainly.com/question/15019502
#SPJ1
Answer:
Following are the responses to the given points:
Step-by-step explanation:
Dilation implies the triangle
stretched through the factor "2".
right triangles:
![\Delta XYZ and \Delta ACB \\\\\angle X \cong \angle A \leftarrow given\\\\](https://tex.z-dn.net/?f=%5CDelta%20%20XYZ%20and%20%5CDelta%20%20ACB%20%5C%5C%5C%5C%5Cangle%20X%20%5Ccong%20%5Cangle%20A%20%5Cleftarrow%20given%5C%5C%5C%5C)
complementary angles:
![\angle X \ and\ \angle Z](https://tex.z-dn.net/?f=%5Cangle%20X%20%5C%20and%5C%20%20%5Cangle%20Z)
![m\angle Z = 90^{\circ} - m\angle X \\\\](https://tex.z-dn.net/?f=m%5Cangle%20Z%20%3D%2090%5E%7B%5Ccirc%7D%20-%20m%5Cangle%20X%20%5C%5C%5C%5C)
complementary angles:
![\angle A \ and\ \angle B](https://tex.z-dn.net/?f=%5Cangle%20A%20%5C%20and%5C%20%20%5Cangle%20B)
![m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta XYZ \sim \Delta ACB \\\\](https://tex.z-dn.net/?f=m%5Cangle%20B%20%3D%2090%5E%7B%5Ccirc%7D%20-%20m%5Cangle%20A%20%5C%5C%5C%5C%5Ctherefore%20%5C%5C%5C%5C%20%5Cangle%20Z%20%5Ccong%20%5Cangle%20B%20%5C%5C%5C%5C%5CDelta%20%20XYZ%20%5Csim%20%20%5CDelta%20ACB%20%5C%5C%5C%5C)
Same triangles: proportional side are corresponding, congruence angles are respective.
Calculating the length of leg XY:
![XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow \ given\\\\AC = 2XY \cong 2 \times 2.4996 \cong 4.999\ (units)\\\\](https://tex.z-dn.net/?f=XY%20%3D%20%5Csqrt%7B%28%285.59%29%5E2%20-%2052%29%7D%20%5Ccong%202.4996%20%28units%29%5C%5C%5C%5C%5Cfrac%7BCB%7D%7BYZ%7D%20%3D%202%20%5Cleftarrow%20given%20%5C%5C%5C%5CCD%20%3D%202YZ%20%3D%202%20%5Ctimes%205%20%3D%2010%20%5C%20%28units%29%5C%5C%5C%5C%5Cfrac%7BAC%7D%7BXY%7D%20%3D%202%20%5Cleftarrow%20%20%5C%20given%5C%5C%5C%5CAC%20%3D%202XY%20%5Ccong%202%20%5Ctimes%20%202.4996%20%5Ccong%204.999%5C%20%20%28units%29%5C%5C%5C%5C)