Using linear function concepts, it is found that:
- a) It costs $0.1 for each kilowatt hour of electricity used in excess of 250 kWh.
- b) f(90) = 46.6, which is the cost of 340 kWh of consumption in a month.
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A <em>linear function </em>has the format given by:
In which:
- m is the slope, which is the rate of change, that is, how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0.
The equation for the cost of h kilowatt hours (kWh) of electricity used in excess of 250 kWh is of:
Item a:
- The slope is of
, which means that it costs $0.1 for each kilowatt hour of electricity used in excess of 250 kWh.
Item b:
250 + 90 = 340.
f(90) = 46.6, which is the cost of 340 kWh of consumption in a month.
A similar problem is given at brainly.com/question/24808124
It’s the second one pls brainliest me
To make a the subject we proceed as follows:
p=2a-3
add 3 on both sides
3+p=2a-3+3
simplifying the above gives us:
3+p=2a
divide both through by 2
3/2+p/2=(2a)/2
thus
a=3/2+p/2
Use distance formula d=sqrt root (y2-y1)^2+(x2-x1)^2. So (-3, 4) and (1, 7). D= sqrt root ( 7-4)^2+(-3+1)^2. So now solve d= sqrt (3)^2+(-2)^2. Now d= sqrt 9+4. D= sqrt 13 or 3.60555
Given:
<span>Face value $4,530,
discount rate 7.2%,
time 125 days
Discount on Simple Discount note:
Discount = Maturity Value * discount rate * term
Discount = 4,530 * 0.072 * 125/360
Discount = 113.25
Proceeds for the simple discount note
Proceeds = Maturity Value - Discount
Proceeds = 4,530 - 113.25
Proceeds = 4,416.75
The proceeds for the simple discount note is $4,416.75</span>
