Question

20y-10x=5 in slope intercept form can you explain the steps

Answer 1

Given:

The equation is

$20y-10x+5$

To find:

The slope intercept form of the given equation.

Solution:

The slope intercept form of a linear equation is

$y=mx+b$

Where, m is slope and b is the y-intercept.

We have,

$20y-10x=5$

We need to isolate y. Add 10x on both sides.

$20y-10x+10x=5+10x$

$20y=5+10x$

Divide both sides by 20.

$\dfrac{20y}{20}=\dfrac{5+10x}{20}$

$y=\dfrac{5}{20}+\dfrac{10x}{20}$

$y=\dfrac{1}{4}+\dfrac{x}{2}$

$y=\dfrac{1}{2}x+\dfrac{1}{4}$

Therefore, the slope intercept form of the given equation is $y=\dfrac{1}{2}x+\dfrac{1}{4}$.