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Elza [17]
3 years ago
5

Given the ABC, where A(4,3), B(2,-1), and C(-2,1). Use the slope and distance formula to classify the triangle.​

Mathematics
2 answers:
rewona [7]3 years ago
6 0

It might be 2 not 100 percent sure

brilliants [131]3 years ago
3 0

Answer:

isosceles (based on sides) and right triangle (based on angles)

Step-by-step explanation:

This is an isosceles triangle because two of the sides are the same distance (it is in cm.). This is also a right triangle because at point B the two lines are perpendicular (using their slopes).

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2 1/6 of the board is left
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3 years ago
I would really appreciate it if someone could answer this I will give a brainlist:)
PilotLPTM [1.2K]

5.7

Pythagorean Theorem is a² + b² =  c²

8 0
3 years ago
Read 2 more answers
consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where
boyakko [2]

Answer:

a)X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

b)Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

Step-by-step explanation:

From the question we are told that

The Function

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

Generally the differentiation of function f(x) is mathematically solved as

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

f(x)=\frac{x^3+x^2+5x+1}{x^2}

Therefore

f'(x)=\frac{x^2+10x+3}{x^4}

Generally critical point is given as

f'(x)=0

\frac{x^2+10x+3}{x^4}=0

x=-5 \pm\sqrt{22}

Generally the maximum and minimum x value for critical point is mathematically solved as

f'(-5 \pm\sqrt{22})

Where

Maximum value of x

f'(-5 +\sqrt{22})

Minimum value of x

f'(-5 +\sqrt{22})

Therefore interval of increase is mathematically given by

f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})

f(x)

Therefore interval of decrease is mathematically given by

(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)

Generally the second differentiation of function f(x) is mathematically solved as

f''(x)=\frac{2(x^2+15x+6)}{x^5}

Generally the point of inflection is mathematically solved as

f''(x)=0

x^2+15x+6=0

Therefore inflection points is given as

x=\frac{1}{2} (-15 \pm \sqrt{201}

f''(x)>0,\frac{1}{2}(-15-\sqrt{201})

a)Generally the concave upward interval X is mathematically given as

X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

f''(x)

b)Generally the concave downward interval Y is mathematically given as

Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

5 0
3 years ago
What is the probability of drawing a black ace followed by a heart out
Verdich [7]

Correct option C) 0.98%

<u>Step-by-step explanation:</u>

We know that  , there are 2 black ace cards out of 52 cards in a deck & 13 hearts out of 52 cards . Here we have to tell What is the probability of drawing a black ace followed by a heart out  of a deck when the cards aren't replaced . Let's find out:

Firstly , a black ace is drawn , so probability :

⇒ P(Black) = \frac{2}{52}

Now , A heart is drawn out of 51 cards ( as one black ace is already drawn !):

⇒ P(Heart) = \frac{13}{51}

So , Probability of occurring both events is :

⇒ P(Black)(P(Heart))

⇒ \frac{2}{52} (\frac{13}{51} )

⇒ 0.0098

Percentage = 0.0098(100) = 0.98%

Therefore , Correct option C) 0.98%

7 0
3 years ago
write the first six terms of the arithmetic sequence with the first term a1 =90 , and common differnce, d=9​
brilliants [131]
Given a1 = 90
Common difference = adding
90 + 9 = 99, second term
99 + 9 = 108, third term
And keep doing that
You would get
90, 99, 108, 117, 126, 135
8 0
3 years ago
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