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Harrizon [31]
2 years ago
11

A ​6000-seat theater has tickets for sale at ​$26 and ​$40. How many tickets should be sold at each price for a sellout performa

nce to generate a total revenue of ​$​185,400?
Mathematics
1 answer:
ss7ja [257]2 years ago
5 0

Answer:

x = number of tickets sold for $26 = 3900 tickets

y = number of tickets sold for $40 = 2100 tickets

Step-by-step explanation:

A ​6000-seat theater has tickets for sale at ​$26 and ​$40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of ​$​185,400?

Let

x = number of tickets sold for $26

y = number of tickets sold for $40

x + y = 6000

x = 6000 - y

$26 × x + $40 × y= $185, 400

26x + 40y = 185400

Substitute

26(6000 - y) + 40y = 185400

156000 - 26y + 40y = 185400

Collect like terms

- 26y + 40y = 185400 - 156000

14y = 29400

y = 29400/14

y = 2100 tickets

x = 6000 - y

x = 6000 - 2100

x = 3900 tickets

Hence

x = number of tickets sold for $26 = 3900 tickets

y = number of tickets sold for $40 = 2100 tickets

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Suppose that the farmer had bought the rice at x dollars per bag and had sold them at a 25% markup.  How much did the bags cost him before he added the markup?  1.25x =$75 results in $75/1.25, or $60 per bag.

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Step-by-step explanation:

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