3x - 5 2x + Find the perimeter

Drag the simplified value into the box to match each expression.

JulijaS [17]

Can you tell me what the expressions, values and all that are
I ca't help with out the details.

7 0

3 years ago

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Hello, can you answer this for me

Elis [28]

Answer:

Steve is 18 and and his mother is 47.

Step-by-step explanation:

if you add those numbers you'll get 65

3 0

3 years ago

The cost of a piece of fabric is $1.32 per yard.

koban [17]

Answer:

1.32 x 3.5= 4.62

..............

4 0

3 years ago

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Find the indicated nth term show your solution 8,15,22,29,...,a18

Damm [24]

Answer:

127

Step-by-step explanation:

Hey there! :)

Let us find the 18th term — first, there are two main types of sequences.

Arithmetic Sequence — a sequence that has same difference or common difference.
Geometric Sequence — a sequence that has same ratio.

But if you notice, it cannot be geometric sequence because if we do ratio test, there are no common ratios.

Hence, it can only be arithmetic sequence.

Common Difference

$\displaystyle \large{a_{n + 1} - a_n = d}$

d is our common difference.

a_n+1 is the next term of a_n.

Let's check the common difference!

15-8 = 7

22-15 = 7

29-22 = 7

Therefore, 7 is our common difference.

General Terms of Arithmetic Sequence

$\displaystyle \large{a_n = a_1 + (n - 1)d}$

We know that a1 is the first term of sequence which is 8.

Our common difference is 7.

We want to find the 18th term — therefore,

$\displaystyle \large{a_{18} = 8 + (18 - 1)7} \\ \displaystyle \large{a_{18} = 8 + (17)7} \\ \displaystyle \large{a_{18} = 8 + 119} \\ \displaystyle \large{a_{18} = 127}$

Therefore, the 18th term is 127.

4 0

3 years ago

Maria wrote the equation log(x/2)+log(20/x^2)=log8. What is the solution to Maria's equation?

Fed [463]

The solution is x=5/4.

We use the properties of logs to rewrite the equation:
$\log[(\frac{x}{2})(\frac{20}{x^2})]=\log8
\\
\\\log(\frac{20x}{2x^2})=\log8
\\
\\\log(\frac{10}{x})=\log8$

Get all of the logs on the same side of the equation y subtracting log 8:
$\log(\frac{10}{x})-\log8=\log8 - \log8
\\
\\\log(\frac{10}{x})-\log8=0$

Use the properties of logs to rewrite:
$\log(\frac{10}{x}\div8)=0
\\
\\\log(\frac{10}{x}\div\frac{8}{1})=0
\\
\\\log(\frac{10}{x}\times\frac{1}{8})=0
\\
\\\log(\frac{10}{8x})=0$

Exponentiate:
$10^0=\frac{10}{8x}
\\
\\1=\frac{10}{8x}$

Multiply both sides by 8x:
1*8x = (10/8x)*8x
8x=10

Divide both sides by 8:
8x/8 = 10/8
x = 10/8 = 5/4

3 0

3 years ago

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