Answer:
Step-by-step explanation:
This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.
x + 1 = 0 so
x = -1
x - 9 = 0 so
x = 9
We all know that time cannot ever be negative, so the time that the object is on the ground is 9 seconds after it's launched (which was from an initial height of 45 meters).
Answer:
1.30 p.M.
Step-by-step explanation:
The factory whistle blowed at 1:00 p.M, and it blows every 30 minutes, so it will blow again at 1:30 p.M.
The clock tower chimed at 1.00 p.M., and it chimes every 15 minutes, so it will chime again at 1:15 p.M, and after that, it will chime again at 1:30 p.M.
So, you will hear them both at the same time at 1:30 p.M.
We can also solve this problem using LCM:
the least commom multiple between 15 and 30 is 30, so we just need to sum 30 to the inicial time (1:00 p.M.), so the time they will "find each other" again is 1.30 p.M.
Answer:
x= 1
y= -1
Step-by-step explanation:
y=-2x+1
2x-2y=4
substitute for y
2x-2(-2x+1)=4
reduce
2x+4x-2=4
6x=6
x=1
y= -2(1)+1
y= -1
I need the whole picture that’s only half
