Your answer is either A or D
Solution :
Amounts spent on a trip : $31.11, $25.01, $18.53, $14.37, $24.16, $21.91
Confidence interval = 80%
Average amount spent = 8 to 9 years old
One sample T confidence interval
μ : Mean of variance
80% of confidence interval results :
Using statistical software,
Variable : data
Sample mean : 22.515
Std. Err. = 2.3479945
DF = 5
L. limit : 19.049632
U. Limit : 25.980368
SD = 5.75
Critical value = 1.476
To find the difference in weights from two years ago, you will need to combine the 2 differences from the two years.
-1.56 and 0.73 becomes -1.56 + 0.73.
To add a positive and a negative number you will subtract the absolute values of the numbers AND use the sign of the number with the bigger absolute value (negative) in your answer.
|-1.56| - |0.73|
1.56 - 0.73 = 0.83
-0.83
The cat lost 0.83 (-0.83) pounds over 2 years.
