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KIM [24]
3 years ago
6

A temperature of 37C is equivalent to a temperature of

Chemistry
2 answers:
ss7ja [257]3 years ago
8 0
Answer 98.6 Fahrenheit
Alex17521 [72]3 years ago
7 0

Answer:

98.6 Degrees Fahrenheit

Explanation:

To convert from Celsius to Fahrenheit, the formula is F=(1.8*C)+32. Since C=37 in this case, our formula is F=(1.8*37)+32. First, solving the work in the parentheses, 1.8*37=66.6. Adding that will get you to 98.6, so F=98.6.

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The law of constant composition states: All atoms of a given element have a constant composition and are different than atoms of
Airida [17]

Answer:

C

Explanation:

The law proves C. For examples no matter how water you have it will always have a 1:2 ratio of oxygen to hydrogen. :)

7 0
2 years ago
In which pair do both compounds exhibit predominantly ionic bonding? A) KCl and CO2 B) SO2 and BaF2 C) F2 and N2O D) N2O3 and Rb
gtnhenbr [62]

Answer:

E) NaF and SrO

Explanation:

The ionic bonding occurs between atoms with a great difference in electronegativity. This usually happens between a metal and a non-metal.

<em>In which pair do both compounds exhibit predominantly ionic bonding? </em>

A) KCl and CO₂. NO. C and O are non-metals and present covalent bonding.

B) SO₂ and BaF₂. NO. S and O are non-metals and present covalent bonding.

C) F₂ and N₂O. NO. Both compounds contain non-metals and present covalent bonding.

D) N₂O₃ and Rb₂O. NO. N and O are non-metals and present covalent bonding.

E) NaF and SrO. YES. Na and Sr are metals while F and O are non-metals.

5 0
3 years ago
Hannah is investigating how all of Earths systems can affect each other at any given moment. What is one way the cryosphere can
snow_lady [41]
The cryosphere can affect the atmosphere by letting the Earth get to warm. The cryosphere protects the Earth from getting to warm.
4 0
3 years ago
Read 2 more answers
What kind of molecule is glucose
Scrat [10]
Organic molecule. In particular,  a carbohydrate.
6 0
3 years ago
What is the hybridization and shape for an XeF6 2+ molecule?
Anna11 [10]

Answer:

Xe:[Kr]4d¹⁰5(sp³d³)₆⁺² => Octahedral Geometry (AX₆)⁺²

Explanation:

Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆²

Ca. #Valence e⁻ = Xe + 6F - 2e⁻ = 1(8) + 6(7) - 2 = 48

Ca. #Substrate e⁻ = 6F = 6(8) = 48

#Nonbonded free pairs e⁻ = (V - S)/2 = (48 - 48)/2 = 0 free pairs

#Bonded pairs e⁻ = 6F substrates = 6 bonded pairs

BPr + NBPr = 6 + 0 = 6 e⁻ pairs => Geometry => [AX₆]⁺² => Octahedron

Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆⁺²    

XeF₆⁺² => 6(sp³d³) hybrid orbitals => Octahedral Geometry (AX₆)      

8 0
3 years ago
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