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liq [111]
3 years ago
7

A stock solution is made by dissolving 66.05 g of (NH4)2SO4 in enough water to make 250 mL of solution. A 10.0 mL sample of this

solution is then diluted to 50.0 mL. Given that the molar mass of (NH4)2SO4 is 132.1 g/mol, what is the concentration of the new solution?
Chemistry
2 answers:
Degger [83]3 years ago
7 0
If the solute is properly distributed in the given volume, there are 2.642 g of (NH4)2SO4 per 10 mL. For the new solution, divide the 2.642 g by the molar mass of the compound. The answer is 0.02 moles. Then, divide this by the new volume, 50 mL or 0.05 L. The concentration of the new solution is 0.4 M. 
Allushta [10]3 years ago
4 0

Answer:

0.400 M

Explanation:

On edge 2020

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a 160 milligram sample of a radioactive isotope decays to 10 kilograms in 12 years. what is the half life of this element
Shkiper50 [21]

Answer:

3 years

Explanation:

Given data:

Initial amount of sample = 160 Kg

Amount left after 12 years = 10 Kg

Half life = ?

Solution:

at time zero = 160 Kg

1st half life = 160/2 = 80 kg

2nd half life = 80/2 = 40 kg

3rd half life = 40 / 2 = 20 kg

4th half life = 20 / 2 = 10 kg

Half life:

HL = elapsed time / half life

12 years / 4 = 3 years

8 0
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melisa1 [442]
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4 0
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slega [8]

Answer:

Anything in the environment that causes a change is called a stimulus.

Explanation:

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What is the theoretical yield of a reaction?
mestny [16]
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4 0
3 years ago
Match the salt with the acid and base used to form it in a neutralizing reaction. K2SO4
emmasim [6.3K]

Answer:

KOH and H₂SO₄

Explanation:

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For example:

2KOH + H₂SO₄  →   K₂SO₄ + 2H₂O

1. Potassium hydroxide and sulfuric acid react to produce potassium sulfate salt and water.

2. Potassium hydroxide and phosphoric acid react to produce potassium phosphate and water.

H₃PO₄  + 3KOH  → K₃PO₄ + 3H₂O

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