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3 years ago

Find the product. (6a + b) 2

Mathematics

1 answer:

I am Lyosha [343]3 years ago

8 0

I think it is 36^2+12ab+b^2

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3 years ago

today only, a suit is being sold at a 29% off (discount). The sale price is $284. What was the original price?

natta225 [31]

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201.64

Step-by-step explanation:

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3 years ago

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The sum of the real numbers x and y is 11. Their difference is 5. What is the value of xy

Veseljchak [2.6K]

Answer:

x=6 y=5

Step-by-step explanation:

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3 years ago

PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!

pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

In this problem, we have that the sine is given by:

$\sin{\theta} = \frac{1}{3}$

Hence, applying the identity, the cosine is given as follows:

$\cos^2{\theta} = 1 - \sin^2{\theta}$

$\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2$

$\cos^2{\theta} = 1 - \frac{1}{9}$

$\cos^2{\theta} = \frac{8}{9}$

$\cos{\theta} = \pm \sqrt{\frac{8}{9}}$

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

The tangent is given by the sine divided by the cosine, hence:

$\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

$\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}$

$\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

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2 years ago

What two inequalities do you get with the absolute value inequality shown below

Setler [38]

Answer:

1st answer

Step-by-step explanation:

x is great than 10 in the question, even if x was negative, the absolute value would still be great than 10 if it says its greater than 10. x is greater than 10 and -10.

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3 years ago