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spayn [35]
3 years ago
9

Each of the following statements describes a quadrilateral. Which of the quadrilaterals are NOT parallelograms? Choose three.

Mathematics
2 answers:
dimaraw [331]3 years ago
8 0

Answer:  The answer is 1, 2 and 4.

Step-by-step explanation:  

(1) The quadrilateral with congruent diagonals but no angle is a right angle is an ISOSCELES TRAPEZOID. So, this will not be a parallelogram.

(2) The quadrilateral with two consecutive congruent sides and is not a rhombus is  a KITE. So, this will not be a parallelogram

(3) A quadrilateral with each diagonal 3 cm long and two opposite sides 2 cm long will be a RECTANGLE. So, this will be a parallelogram.

(4) A quadrilateral with two opposite angles as right angles is not a rectangle will be a KITE. so, this will also be not a parallelogram.

(5) A quadrilateral in which one diagonal is a perpendicular bisector of the other will be a SQUARE. So, this will be a parallelogram.

Thus, (1), (2) and (4) are the correct options.

Elina [12.6K]3 years ago
4 0
1 st 2nd and 4th are NOT parallelograms.
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In the 3rd hour, they sold (33/4 + 3/4) = 36/4 = 9.  They had (33-9) = 24 left.

In the final hour, they sold (24/5 + 1/5) = 25/5 = 5.  They had (24-5) = 19 left.  yay!

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The key to solving this one is to work it backwards.

-- They had 19 peaches left at the end of the day.

-- During the final hour, the 1/5 of a peach that they sold left them with 19,
so they had 19-1/5 before they sold the 1/5 of a peach.
The 19-1/5 was 4/5 of what they had at the beginning of the final hour.
So, at the beginning of the final hour, they had (5/4)x(19.2) = 24 .

-- During the 3rd hour, the 3/4 of a peach that they sold left them with 24,
so they had 24-3/4 before they sold the 3/4 of a peach.
The 24-3/4 was 3/4 of what they had at the beginning of that hour.
So, at the beginning of the 3rd hour, they had (4/3)x(24.75) = 33 .

Do the same for the 2nd hour.

Then do the same for the 1st hour.

And you'll work your way back up to 101 peaches.


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