Answer:
the hawk has flow 824.62 meters southwest of the mountain peak.
Step-by-step explanation:
In order to find the distance we need to use the Pythagoras theorem
d^2 = 800^2 + 200^2
d= 824.6 m
we can find the direction by using the eq for a tangent
he opposite side is 200 m and the adjacent side is 800m
tan theta = opposite / adjacent
theta = arc tan (800/200)
The hawk is at a distance of 824.6m flying at an angle 76 degrees NE of the mountain peak.
The final location will be southwest of the mountain peek.
a2+b2=c2
a = 200
b= 800
c = √(2002+8002) = 824.62
So the hawk has flow 824.62 meters southwest of the mountain peak.
Answer:
Centre of Gravity or Gravitational Force
Step-by-step explanation:
The main lesson students and teachers should take away from this problem is the correct answer should be:
who cares? The group built their frames with a ruler and a saw, got an
exact slope of 10/3 and the angle measures didn't matter one bit. The best angles measures are the ones avoided.
But trig as taught is all about angles. Gotta find the angle. Here we have a right triangle and we're interested in the angle at the top of the frame, opposite side 3, adjacent side 10, so
Answer:
<u>f(x)=x²-2x-2</u>
Step-by-step explanation:
<em><u>f(x)=ax²+bx+c</u></em>
f(0)=-2 => c= -2
f(1)= -3=> a+b-2=-3; a+b=-1
f(2)= -2; 4a+2b-2=-2; 4a+2b=0; 2a+b=0
a+b=-1 and 2a+b=0
2a+b-(a+b)=0+1=> a=1
2+b=0=> b=-2
f(x)=x²-2x-2
I think the answer is the last one.
