A theater production group is making frames to support wall-like props. Three-foot beams form right triangles with 10-foot beams
2 answers:
The main lesson students and teachers should take away from this problem is the correct answer should be: who cares? The group built their frames with a ruler and a saw, got an exact slope of 10/3 and the angle measures didn't matter one bit. The best angles measures are the ones avoided.
But trig as taught is all about angles. Gotta find the angle. Here we have a right triangle and we're interested in the angle at the top of the frame, opposite side 3, adjacent side 10, so
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Answer:
(2,-5) and (2,1).
Step-by-step explanation:
We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.
A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.
Standard form of a circle is
where, (h,k) is center and r is the radius.
Now, put x=2.
Taking square root on both sides.
So, the y-coordinates of the points are -5 and 1.
Therefore, the required points are (2,-5) and (2,1).
Answer:
Answer is d - x =
Step-by-step explanation:
Step 1: Add 'z' to both sides
4x -z (+z) = y + z
4x = y + z
Step 2: To solve for x, divide both sides by 4
=
x =
Answer: They are not perpendicular because their slopes are not negative reciprocals.
Step-by-step explanation:
For these two lines to be perpendicular, their slopes have to be negative reciprocals.
Slope of FG.
F = (-4, 1)
G = (0, -2)
= (Y₂ - Y₁) / (X₂ - X₁)
= (-2 - 1) / (0 + 4)
= -3/4
Slope of HJ
J = (0 , 4)
H = (-4, -2)
Slope = (Y₂ - Y₁) / (X₂ - X₁)
= (-2 - 4) / (-4 -0)
= 6/4
= 3/2
<em>The slopes of these lines are not negative reciprocals so these lines are not perpendicular. </em>
