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Delicious77 [7]
3 years ago
11

Assuming 84.0% efficiency for the conversion of electrical power by the motor, what current must the 13.0-V batteries of a 716 k

g electric car be able to supply to climb a 3.00 x 102 m high hill in 2.00 min at a constant 22.0 m/s speed while exerting 7.00 x 102 N of force to overcome air resistance and friction
Physics
1 answer:
tino4ka555 [31]3 years ago
8 0

Answer:

\mathbf{ current(I) =1766.67 \ A}

Explanation:

Given that:

The air resistance and friction = 700 N

The gravity caused force = 716 × 9.8 = 7016.8

Total force = (7016.8 + 700) N

Total force = 7716.8 N

∴

13 \times  current(I) \times 0.84 = \dfrac{7716.8 \times 300}{2 \times 60}

current(I) \times 10.92= 19292

current(I) = \dfrac{19292}{10.92}

\mathbf{ current(I) =1766.67 \ A}

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3 years ago
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The Hall effect is to be used to find the sign of charge carriers in a semiconductor sample. The probe is placed between the pol
Alborosie

Answer:

the sign of these carriers is POSITIVE

Explanation:

In the effect, he found the charge carriers that were subjected to two forces, one electric and the other magnetic.

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bold indicates vectors

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In the exercise they indicate that the north side has a higher potential than the south side, therefore there must be an accumulation of carriers on this side that create an electric field (Hall) that is put to the magnetic force until reaching equilibrium when the total force is zero.

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6 0
3 years ago
1. If a 25 kg car accelerates at a speed of 100m/s2,2 what will the force of the car be?
algol13

Answer:

F = 2500N

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F = ma

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4 0
4 years ago
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Explanation:

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