Explanation:
The velocity of sound depends on the density of the medium. So we need to find the density of air at each set of conditions. The density of air is:
ρ = (Pd / (Rd T)) + (Pv / (Rv T))
where Pd and Pv are the partial pressures of dry air and water vapor,
Rd and Rv are the specific gas constants of dry air and water vapor,
and T is the absolute temperature.
At the first condition:
Pv = 31.7 mmHg = 4226.3 Pa
Pd = 650 mmHg - 31.7 mmHg = 618.3 mmHg = 82433 Pa
Rv = 461.52 J/kg/K
Rd = 287.00 J/kg/K
T = 30°C = 303.15°C
ρ = (82433 / 287.00 / 303.15) + (4226.3 / 461.52 / 303.15)
ρ = 0.94746 + 0.03021
ρ = 0.97767 kg/m³
At the second condition:
Pv = 0 Pa
Pd = 650 mmHg = 86660 Pa
Rv = 461.52 J/kg/K
Rd = 287.00 J/kg/K
T = 0°C = 273.15°C
ρ = (86660 / 287.00 / 273.15) + (0 / 461.52 / 273.15)
ρ = 1.1054 + 0
ρ = 1.1054 kg/m³
The square of the velocity of sound is proportional to the ratio between pressure and density:
v² = k P / ρ
Since the atmospheric pressure is constant, we can say it's proportional to just the density:
v² = k / ρ
Using the first condition to find the coefficient:
(340)² = k / 0.97767
k = 113018.652
Now finding the velocity of sound at the second condition:
v² = 113018.652 / 1.1054
v = 319.75
Answer:
Your answers would be
4. A. sperm and testosterone.
7. C. prostate, penis, Testes
uterus, vagina, fallopian tubes
10. B. Protein
11. A. carbohydrate
12. B. amino acids (I'm not positive on this i haven't taken bio in years
27. D. Respiratory system
Explanation:
yeah
Answer:
all of the above
PLS MARK ME AS BRAINLIAST
Answer:
Mass of the car is 1576 kg.
Explanation:
Let the mass of the car be 
kg.
Given:
Initial velocity of the car is, 
As the car stops, final velocity of the car is, 
Change in momentum is, 
Now, we know that, momentum is given as the product of mass and velocity.
So, change in momentum is given as:
Therefore, the mass of the car is 1576 kg.
Answer:
Smallest drop: Water
Largest drop: Dirt
Explanation:
The heat needed to change the temperature of a sample is:
(1)
with Q the heat (added(+) or removed(-)), c specific heat, m the mass and 
the change in temperature of the sample. So, if we solve (1) for
Sample A:
Sample B:
Sample C:
Note that the numbers 16744, 5400, 9450 are in the denominator of the expression 
that gives the drop on temperature. so, if Q is the same for the three samples the smallest denominator gives the largest drop and vice versa.
So, the smallest drop is Sample A and the largest is Sample C.
(Important: The minus sign of implies the temperature is dropping)
