Answer:
Mintu should have chosen material with lower specific heat.
Hope this is useful!! <3
Work, in physics, is the force exerted or applied in order to move an object to a certain distance. It is calculated from the product of force and the distance. It is the energy that is transferred during the movement. It will have units of N-m which is equivalent to J, a unit of energy. We calculate as follows:
Work = Force x distance
Work = 20 N x 2 m
Work = 40 N-m or 40 J
<h3><u>Answer;</u> </h3>
= 0.03066 m
<h3><u>Explanation;</u></h3>
Work done or energy by a spring or an elastic material is given by the formula;
Potential energy = 1/2 kx²
Where, k is the spring constant and x is the distance stretched.
Therefore;
47 J = 1/2 (100000 n/m) x²
47 J = 50, 000 x²
x² = 47 /50,000
x² = 0.00094
x = 0.03066 m
Therefore,<u> x = 0.03066 m </u>
Answer:
<h2>103 Joules</h2>
Explanation:
In this problem we are required to find the potential energy possessed by the television
Given data
mass of television m = 15 kg
height added above the ground, h= 1-0.3 = 0.7 m
acceleration due to gravity g = 9.81 m/s^2
apply the formula for potential energy we have
P.E= m*g*h
P.E = 15*9.81*0.7 = 103 Joules
Answer:
11.07Hz
Explanation:
Check the attachment for diagram of the standing wave in question.
Formula for calculating the fundamental frequency Fo in strings is V/2L where;
V is the velocity of the wave in string
L is the length of the string which is expressed as a function of its wavelength.
The wavelength of the string given is 1.5λ(one loop is equivalent to 0.5 wavelength)
Therefore L = 1.5λ
If L = 3.0m
1.5λ = 3.0m
λ = 3/1.5
λ = 2m
Also;
V = √T/m where;
T is the tension = 0.98N
m is the mass per unit length = 2.0g = 0.002kg
V = √0.98/0.002
V = √490
V = 22.14m/s
Fo = V/2L (for string)
Fo = 22.14/2(3)
Fo = 22.14/6
Fo = 3.69Hz
Harmonics are multiple integrals of the fundamental frequency. The string in question resonates in 2nd harmonics F2 = 3Fo
Frequency of the wave = 3×3.69
Frequency of the wave = 11.07Hz