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2 years ago

Question 1

Mathematics

1 answer:

Readme [11.4K]2 years ago

8 0

Answer:

Step-by-step explanation:

0.41

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Is 3x + 2y = 6 a function??

mel-nik [20]

Answer:

Step-by-step explanation:

2y=-3x+6

y = -0.5x + 3

this is a function because it is a linear equation that isn’t undefined

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2 years ago

Help me plz add or subtract the following fraction answer the lowest terms.

Stels [109]

1. =4/16 which in simplified terms = 1/4

2. = 37/99 (find the lowest common denominator which is 99 then multiply them, then combine fractions then subtract them)

3. 2/25

4. 12/18 which simplified is 2/3

5. 5/15 which simplified = 1/3

Hope you understand that:)

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2 years ago

What is NOT a way to write 52 + 80? 50 + 2 + 80 (50 + 80) + 2 50 + 80 + 2 + 8 50 + 2 + 80 + 0

GuDViN [60]

Answer: 52-80

Step-by-step explanation:

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2 years ago

Read 2 more answers

Michelle went on a hike. She started on the trail at 6:45 a.m and returned at 3:28 p.m. How long did she hike?

Lerok [7]

D. Because if one time is a certain amount of time away from 12pm and the other one is a certain amout away from 12pm then you add them up and get a number of hours and minutes

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2 years ago

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The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

2 years ago