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3 years ago

Solve for x, round to the nearest hundredths place.

Mathematics

1 answer:

Maurinko [17]3 years ago

3 0

Answer:

2.33333

Step-by-step explanation:

mark me as brainliest

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If f(x)=2x²-x-6 and g(x)=x²-4, find f(x)÷g(x)

GuDViN [60]

Fx=2x2-x-6 Gx=x2-4
Fx÷Gx
2x2-x-6/x2-4
Simplify
2x+3 x-2/ x-2 x+2
You can cancel out x-2 since they are on both top n bottom
2x+3/x+2 answer is C

5 0

2 years ago

Zachery is solving the equation 3/4 (x - 8) = 12

Maru [420]

Answer:

3/4*x - 3/4*8=12

3/4x -6=12

3/4x=12+6

3/4x=18

x=24

Step-by-step explanation:

multiply 3/4 into the content inside the brackets

have -3/4*8 cross the equal sign changing its sign from - to +

divide both sides by 3/4

6 0

2 years ago

Estimate.Then find the differences and write it in simplest form.

Rama09 [41]

D . internal............

7 0

3 years ago

PLEASE HELP ME THIS IS DUE ASAP!!! I will mark brainliest if right!!! Explain!

Fed [463]

Answer:

Step-by-step explanation:

6 0

2 years ago

On which interval is the average rate of change for bicycle production the greatest? A) 1950 to 1960 B) 1960 to 1970 C) 1970 to

Alborosie

Answer:

D) 1980 to 2000

Step-by-step explanation:

Finding the average rate of change in each interval to determine the greatest one.

Production per interval

1950-1960 = $(21-11) \ million$ = 10 million

1960-1970 = $(41-21)\ million$ = 20 million

1970-1980 = $(71-41)\ million$ = 30 million

1980-2000 = $(161-71)\ million= 90$ million

Rate of change (1950-1960)= $\frac{10}{11} \times 100= 90.90\%$

Rate of change (1960-1970) = $\frac{20}{21} \times 100= 95.23\%$

Rate of change (1970-1980)= $\frac{30}{41} \times 100= 73.17\%$

Rate of change (1980-2000)= $\frac{90}{71} \times 100= 126.76\%$

∴ rate of change between 1980 to 2000 is 126.78%

7 0

2 years ago