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Oksana_A [137]
3 years ago
12

State the slope of the line shown below. 0 1 –2 undefined

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
7 0

Answer: 0

Step-by-step explanation:

From then given graph , it can be seen that the line is parallel to x axis passing through y=-2.

We know that if two lines are paralleled then they have equal slope.

We know that the slope of x-axis is 0.

[∵\text{Slope=}\dfrac{\text{Change in y coordinates}}{\text{Change in x coordinates}}=\dfrac{0}{\text{Chnage in x coordinates}}=0]

Hence, the slope of the given line =0

Paladinen [302]3 years ago
5 0
The slope would be 0 because the line does not intersect the x - axis.
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Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
3 years ago
The table and the graph each show a different relationship between the same two variables, x and y:
SCORPION-xisa [38]
When x=2 y = 110 which means when when x=1 y = 55
the graph would be 11*55 or 605
The table would be 280/4= 70 70*11=770 
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165 is ur answer
7 0
3 years ago
Evaluate the expression ab for a = 10 and b = 4.
xz_007 [3.2K]

A x B

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3 years ago
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Answer:

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Step by step explanation-

Given-

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Now,

<h3>\mathfrak {circumference \: of \: circle = \pi d }</h3>

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\:  \:  \:  \:  \:  \:  \:\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \boxed{  = 72.22 \: units}

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neonofarm [45]

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A. 2.25 and 0.5

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