Speed=distance/time
average speed=(total distance)/(total time)
total distance=203+243=446
total time=3.5+4.5=8
average speed=(446)/(8)=55.75
answer is A
Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
Any arithmetic sequence can be expressed as:
a(n)=a+d(n-1), a=initial term, d=common difference, n=term number
In this case a=5, and d=-2 so
a(n)=5-2(n-1) which can be simplified...
a(n)=5-2n+2
a(n)=7-2n
The domain is restricted to integers from 1 to +oo.
Explanation: Given: Clayton bikes 3/8<span> of </span>14.5 miles<span>. </span>38⋅14.5<span>1=43.58=5.4375 </span>miles biked<span>. Left to </span>bike<span> to </span>beach<span>: 14.4−5.4375=9.0625 </span>miles<span>. OR. </span>38 biked<span>, means 58 left to </span>bike: 58⋅14.5<span>1=72.58=9.0625 </span>miles<span>. Was this helpful? </span>
You can pack up to 10 1/5 pounds more stuff without going over
