A=9
B=11
C=12
D=15
THE LENGTH OF THE LARGEST POSSIBLE SIDE IS
or,9+11+12+15
or,47 answer
The Priority is always to parenthesis. It means that in both equations, begin by operating what's inside the parenthesis. Then Subtract what's left.
For the first one you get:
For the second one you get:
Which mean that The 2 equations are not equal, because
Hope this Helps! :D
Answer:
9 < x
Step-by-step explanation:
5x - 47< 3(12x - 108) – 2
Distribute
5x - 47< 36x - 324 – 2
Combine like terms
5x - 47< 36x-326
Subtract 5x from each side
5x-5x - 47< 36x-5x-326
- 47< 31x-326
Add 326 to each side
326 - 47< 31x-326+326
279 < 31x
Divide by 31 on each side
279/31 < 31x/31
9 < x
Answer:
A
Step-by-step explanation:
A: The student incorrectly divided both sides by 35. The student should first add 10 to both sides, obtaining 35x = 15, and then divide 15 by 35, obtaining the final answer 3/7.
Step-by-step explanation:
x² + 6x + 9 = 2
(x + 3)² = 2
x + 3 = ±sqrt(2)
x = -3 ± sqrt(2)
so, B and D are correct.
control :
(-3 + sqrt(2))² + 6(-3 + sqrt(2)) + 9 = 2
9 + 2 - 6sqrt(2) - 18 + 6sqrt(2) + 9 = 2
2 = 2
correct
(-3 - sqrt(2))² + 6(-3 - sqrt(2)) + 9 = 2
9 + 2 + 6sqrt(2) - 18 - 6sqrt(2) + 9 = 2
2 = 2
correct
(3 + sqrt(2))² + 6(3 + sqrt(2)) + 9 = 2
9 + 2 + 6sqrt(2) + 18 + 6sqrt(2) + 9 = 2
38 + 12sqrt(2) = 2
wrong.
(3 - sqrt(2))² + 6(3 - sqrt(2)) + 9 = 2
9 + 2 - 6sqrt(2) + 18 - 6sqrt(2) + 9 = 2
38 - 12sqrt(2) = 2
wrong.
