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Nadusha1986 [10]
2 years ago
8

what quadrilateral has exactly two pairs of consecutive angles that are supplementary and none of the opposite angles are congru

ent?
Mathematics
1 answer:
Scrat [10]2 years ago
8 0

Answer:

If a quadrilateral is a parallelogram, then consecutive angles are supplementary. If both pairs of opposite sides of a quadrilateral are congruent, then the quadrilateral is a parallelogram.

Step-by-step explanation:

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There were 56 females and 84 males present at the high school pep rally. Find the ratio of males to the total number of people p
irina [24]

Answer:

So first you would add the to numbers 56+84 to get 140. then you would put it in fraction form of males to total people (56/140). Then by simplifying you would get the answer of 2/5!

Step-by-step explanation:

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2 years ago
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I need you To reply To This question I need numbers 14-17
slava [35]
The area of a circle is:
\pi \times r \times r
"r" being the radius and π being 3.14
14. The diameter is 12. So, to get the radius, we would need to halve it. So, the radius would be 6.
Now we plug in 6 for r and 3.14 for π which makes it
3.14 \times 6 \times 6
which equals 113.04
15. The diameter is 9, so to get the radius we need to halve it to get 4.5
Plug in 4.5 for r and 3.14 for π and we get
3.14 \times 4.5 \times 4.5
which equals 63.585
16. The diameter is 18, so to get the radius we need to halve it to get 9
Plug in 9 for r and 3.14 for π and we get
3.14 \times 9 \times 9
which equals 254.34
17. The diameter is 8, so to get the radius we need to halve it to get 4.
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3 0
3 years ago
Please help i’m having a hard time answering it
pshichka [43]
So we know 5ft to 1cm then
4x5=20ft
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8 0
3 years ago
Interpreting composite functions in the real world The volume of air in a balloon is represented by the function v(r)=4/3 ³, whe
adoni [48]

There are two <em>true</em> statements:

  1. When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
  2. V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.

<h3>How to use composition between two function</h3>

Let be <em>f</em> and <em>g</em> two functions, there is a composition of <em>f</em> with respect to <em>g</em> when the domain of <em>f</em> is equal to the range of <em>g</em>. In this question, the <em>domain</em> variable of the function V(r) is replaced by substitution.

If we know that V(r) = (4/3) · π · r³ and r(t) = (1/4) · t², then the composite function is:

V(t) = (4/3) · π · [(1/4) · t²]³

V(t) = (4/3) · π · (1/64) · t⁶

V(t) = (1/48) · π · t⁶

There are two <em>true</em> statements:

  1. When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
  2. V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.

To learn on composition between functions: brainly.com/question/12007574

#SPJ1

7 0
2 years ago
Om to 4conm.
max2010maxim [7]
The correct answer is water
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3 years ago
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