Using the given equation, it is found that it lands on the ground after 0.875 seconds.
<h3>What is the equation for the projectile's height?</h3>
It is given by:
In which:
- v is the initial velocity.
In this problem, considering that the projectile jumps straight into the air with an initial vertical velocity of 14 ft/s, the parameters are v = 14 and h = 0, hence:
It lands on the ground when h(t) = 0, hence:
Then:
It lands on the ground after 0.875 seconds.
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The expanded form could be:
.300+.060+.008
LxW = 4x4.5=18ft^2 cut in half thats 9ft^2
* The force of friction acts in opposite direction in which the surface is having tendency to move .
* the force of friction is equal to force applied to surfaces , so long as surface is at rest .
Distance of earth from the sun = 1.5 x 10⁸ km
speed of light = 3 x 10⁸ m/s
time in minutes = ?
by using the formula,
Distance = velocity x time, we get
time = distance/velocity
time = t = (1.5 x 10⁸) / (3 x 10⁸) = 0.5 seconds
convert 0.5 seconds to minutes = 0.00833333
it takes 0.00833333 minutes to travel from the sun to the earth