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Lesechka [4]
3 years ago
8

How to simplify using distributive -8(x + 4)

Mathematics
1 answer:
slega [8]3 years ago
6 0
-8x-32 is the answer
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Find the HIGHEST Common<br> and lowest common multple<br> of 36 and 48 using<br> prime factors
Vesnalui [34]

Answer:

Step-by-step explanation:

Least common multiple can be found by multiplying the highest exponent prime factors of 36 and 48. First we will calculate the prime factors of 36 and 48.

Prime Factorization of 36

Prime factors of 36 are 2, 3. Prime factorization of 36 in exponential form is:

36 = 22 × 32

Prime Factorization of 48

Prime factors of 48 are 2, 3. Prime factorization of 48 in exponential form is:

48 = 24 × 31

Now multiplying the highest exponent prime factors to calculate the LCM of 36 and 48.

LCM(36,48) = 24 × 32

LCM(36,48) = 144

List of positive integer factors of 36 that divides 36 without a remainder.

1, 2, 3, 4, 6, 9, 12, 18

Factors of 48

List of positive integer factors of 48 that divides 36 without a remainder.

1, 2, 3, 4, 6, 8, 12, 16, 24

Greatest Common Factor Number

We found the factors and prime factorization of 36 and 48. The biggest common factor number is the GCF number.

So the greatest common factor 36 and 48 is 12.

4 0
3 years ago
Read 2 more answers
Solve on the interval (0,2pi)<br><br> 3 cscx-1=2
Musya8 [376]

Answer:

It is pi/2

Step-by-step explanation:

5 0
3 years ago
2/6+1/4<br> Show work please<br> And no links
docker41 [41]

Answer:

7/12

Step-by-step explanation:

1/3+1/4

convert to twelfths

4/12+3/12

7/12

4 0
3 years ago
Read 2 more answers
As a project for math class, two students devised a game in which 3 black marbles and 2 red marbles are put into a bag.
9966 [12]

Answer:

The first option

Step-by-step explanation:

The correct answer is the first option, since E(black) = 0.24 and E(red) = 0.16, Seth should choose to play black marbles.

7 0
3 years ago
Which equations are true?
Maru [420]

Answer:

0=0+x-x

Step-by-step explanation:

for example... plug in any number for x

0=0+5-5

7 0
3 years ago
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