Answer:Let the two unknown numbers be x and y.
So, x-y=40 ........Equation 1
And 0.3(x)= 37.5/100 (y)
From equation 1, x=40+y
Now, multiply through by 100 in equation 2.
We have,
30x = 37.5 (y)
We can multiply through by 10 again,so that the number on the L.H.S becomes a whole number.
Therefore, we have
300x = 375 (y)
Put "x=40+y" in the equation above
That is, 300 (40+y) = 375 (y)
1200 + 300y = 375y
1200 = 375y - 300y
1200 = 75y
Divide both sides by 75 to get your y
Therefore, y =16
From equation 1, we had x= 40 + y
Therefore X = 40 + 16
X= 56
Therefore the two unknown numbers are 56 and 16 respectively.
Step-by-step explanation:
Let us assume the two unknown numbers to be "x" and "y".
Then
x + y = 37
And
xy = - 210
x = - 210/y
Now let us put the value of "x" in the first equation, we get
x + y = 37
- (210/y) + y = 37
y^2 - 210 = 37y
y^2 - 37y - 210 = 0
y^2 - 42y + 5y - 210 = 0
y(y - 42) + 5(y - 42) = 0
(y - 42)(y + 5) = 0
So when
y - 42 = 0
y = 42
Then
x = -(210/42)
= - 5
Again when
y + 5 = 0
y = -5
Then
x = 42
So the two unknown numbers are 42 and -5. I hope the procedure is clear enough for you to understand.
Answer:
4(x+8)
Step-by-step explanation:
hope this helps
Then if you want to know the value of x.
This is the solution 4(x+8)
4x+32 to find the x divide both by side by 4.
4x/4+32/4
x=8
