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DiKsa [7]
3 years ago
8

Perform the division write the result in STANDARD form. Show your work. 2+i/7-i

Mathematics
1 answer:
jarptica [38.1K]3 years ago
4 0

9514 1404 393

Answer:

  0.26 +0.18i

Step-by-step explanation:

Multiply numerator and denominator by the conjugate of the denominator.

  \dfrac{2+i}{7-i}=\dfrac{(2+i)(7+i)}{(7-i)(7+i)}=\dfrac{13+9i}{50}=\boxed{0.26+0.18i}

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Solve: x^2 – 16x + 63 < 0 ​
marysya [2.9K]

Answer:

7 < x < 9

Step-by-step explanation:

x^2 – 16x + 63 < 0

this is a parabola that opens up.

The parabola will be < 0 for values between the roots.

to picture this see the graph below.

Factor

(x - 7)(x - 9) < 0

Roots

x = {7, 9}

solution

7 < x < 9

8 0
3 years ago
What is the vertex of the parabola in the graph
svlad2 [7]

Answer:

(-3,-4)

Step-by-step explanation:

The vertex is where the parabola curves.

4 0
3 years ago
How to simplify this problem: (4c^4)^3
hjlf

Answer:

64c^12

Step-by-step explanation:

(4c^4)^3 distribute exponents

{(4)^3 (C^12)} simplify

64c^12

7 0
3 years ago
32+2/3(21y-6) in factored form
artcher [175]

Answer:

14(y + 2).

Step-by-step explanation:

32 +2/3(21y - 6)

Distributing the 2/3 over the parentheses:

= 32 + 2/3*21y  + 2/3 * -6

= 32 + 14y - 4

= 14y + 28

= 14(y + 2).

6 0
3 years ago
A 2012 Gallup poll surveyed Americans about their employment status and whether or not they have diabetes. The survey results in
posledela

A) See picture for the table.

To make the table, multiply 47774 by 1.5% to get total that have diabetes and multiply 5855 by 2.5% to get total unemployed that have it, then using subtraction fill in the other squares of the table.

B)

Hypothesis:

H0: No association between employment and diabetes.

H1: Association between the two

Using a graphing calculator or Excel, run a chi-test.

Chi squared equals 31.844 with 1 degrees of freedom.

 The two-tailed P value is less than 0.0001

With this information we can reject the null hypothesis and conclude there is an association between diabetes and employment.

C)

Although there is a statistical significance, there really is no practical significance between an incidence rate of 1.5 or 2.5%

3 0
3 years ago
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