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kozerog [31]
4 years ago
6

You preform an experiment to determine how many breaths a fish takes per minute. Your experiment yields the following data: minu

te 1: 65 breaths; minute 2: 73 breaths; minute 5; 62 breaths. Calculate the average number of breaths that a fish takes per minute.
Mathematics
2 answers:
Alex777 [14]4 years ago
8 0

Alright, lets get started.

experiment yields the following data: minute 1: 65 breaths; minute 2: 73 breaths; minute 5: 62 breaths

Total number of breaths = 65+73+62 = 200

Total minutes observes = 3 minutes

So, average breaths per minute will be = \frac{200}{3}=66.67

So, the average number of breaths that a fish takes per minute is 66.67.  :    Answer

Hope it will help :)



Step2247 [10]4 years ago
8 0

Answer:

The average number of breaths that a fish takes per minute is 66.67

Step-by-step explanation:

Consider the provided information.

Your experiment yields the following data: minute 1: 65 breaths; minute 2: 73 breaths; minute 5; 62 breaths.

The formula for calculating average is:

Average=\frac{\text{Sum of observations}}{\tex{Number of observations}}

Sum of observations = 65+73+62 = 200

Number of observations = 3

Now use the above formula to calculate the average.

Average=\frac{200}{3}

Average=66.67

Hence, the average number of breaths that a fish takes per minute is 66.67

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Answer:

49.87% of the population has a heart rate between 68 and 77.

Step-by-step explanation:

We are given that the mean of the data for the resting heart of adults is 68 beats per minute and the standard deviation is 3 beats per minute.

Let X = <u><em>the data for the resting heart of adults</em></u>

The z-score probability distribution for the normal distribution is given by;

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where, \mu = population mean = 68 beats per minute

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Now, the percentage of the population that has a heart rate between 68 and 77 is given by = P(68 < X < 77)

    P(68 < X < 77) = P(X < 77) - P(X \leq 68)

    P(X < 77) = P( \frac{X-\mu}{\sigma} < \frac{77-68}{3} ) = P(Z < 3) = 0.9987

    P(X \leq 68) = P( \frac{X-\mu}{\sigma} \leq \frac{68-68}{3} ) = P(Z \leq 0) = 0.50

The above probability is calculated by looking at the value of x = 3 and x = 0 in the z table which has an area of 0.9987 and 0.50 respectively.

Therefore, P(68 < X < 77) = 0.9987 - 0.50 = 0.4987 or 49.87%

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Step-by-step explanation:

In the figure attached,

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