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Neko [114]
3 years ago
5

Please help me i am very lost

Chemistry
1 answer:
VLD [36.1K]3 years ago
6 0

Answer:

i think that's number D.

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Consider the reaction. mc014-1.jpg How many grams of methane should be burned in an excess of oxygen at STP to obtain 5.6 L of c
garri49 [273]
The reaction for the combustion of methane can be expressed as follows.
                           CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
                            moles of CO2 = (5.6 L) / (22.4 L/1 mole)
                             moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
                              moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
                                                    = 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane. 
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Nanh2 ch3cl reaction
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Murljashka [212]
The Lewis structure of Chloroacetate (H₂CClCO₂) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with CH₂Cl and O⁻.

Formal Charge;
                        Formal charge is caculated as,

Formal charge  =  # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]

Formal charge on Oxygen (Highlighted Red);

Formal charge  =  6 - [ 6 + 2/2]

Formal charge  =  6 - [6 + 1]

Formal charge  =  6 - [7]

Formal charge  =  -1

8 0
3 years ago
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