All categories

3 years ago

Find the diameter of the sphere with the volume of 36 pi cubic units

Mathematics

1 answer:

kobusy [5.1K]3 years ago

4 0

Answer:

${ \tt{volume = \frac{4}{3} \pi {r}^{3} }} \\ 36\pi = \frac{4}{3} \pi \times {(2d)}^{3} \\ \frac{36 \times 3}{4} = 8 {d}^{3} \\ 27 = 8 {d}^{3} \\ {d}^{3} = \frac{27}{8} \\ diameter = 1.5 \: units$

You might be interested in

After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i

Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume ( $V$ ) is calculated by:

$V = \frac{4\pi}{3}\cdot R^{3}$

Where $R$ is the radius of the tumor.

The percentage decrease in the volume of the tumor ( $\%V$ ) is expressed by:

$\%V = \frac{\Delta V}{V_{o}} \times 100\,\%$

Where:

$\Delta V$ - Absolute decrease in the volume of the tumor.

$V_{o}$ - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

$\Delta V = V_{o}-V_{f}$

$\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})$

The percentage decrease is finally simplified:

$\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%$

Given that $R_{o} = R$ and $R_{f} = 0.77\cdot R$ , the percentage decrease in the volume of tumor is:

$\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%$

$\%V = 54.34\,\%$

The volume of the tumor experimented a decrease of 54.34 percent.

5 0

3 years ago

The sum of a number and 17 is no less than 26

Eva8 [605]

I believe it would be as following:

x+7>12

Here, x represents the unknown number. The symbol for no less than is greater than.

5 0

3 years ago

Read 2 more answers

What is 3/7 rounded to a. 0 b. 1/2 c. 1

Dmitry_Shevchenko [17]

Answer: b. 1/2.

Step-by-step explanation: 3/7 in decimal form is 0.42, which is close to 1/2 (0.5) than to 0.

5 0

3 years ago

What is quartile 1 (Q1)quartile 3 (Q3) and the IQR? Answer all three parts . 13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50

Fittoniya [83]

Answer:

Quartile 1 (Q1) = 24

Quartile 2 (Q2) = 47

IQR = 23

Step-by-step explanation:

Given:

The set of data are:

13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50

The data are in increasing order. The number terms are, $n = 11$ .

Therefore, the middle term = $\frac{n+1}{2}=\frac{11+1}{2}=6^{th}\ term$

So, the median = 26

Now, the median divides the set of data into two parts. The median of first part is the quartile 1 and the median of second part is quartile 2.

So, the first part has the following terms:

13, 23, 24, 25, 26

Here also, $n=5$ . So, the third term is the median.

∴ Q1 = 24

The second part has the following terms:

37, 47, 47, 48, 50

Here also, $n=5$ . So, the third term is the median.

∴ Q2 = 47.

Now, IQR = Q2 - Q1 = 47 - 24 = 23.

7 0

4 years ago

What does 4 3/10 equal

Dmitriy789 [7]

Using your talking about putting it into an improper fraction. it would be 43/10.

7 0

3 years ago