The answer is that (It’s 6.6)
Given:
The function, f(x) = -2x^2 + x + 5
Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5
The discriminate b^2 - 4ac = 41
To solve for the zeros of the quadratic function, use this formula:
x = ( -b +-√ (b^2 - 4ac) ) / 2a
x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35
Therefore, the zeros of the quadratic equation are 1.85 and -1.35.
Answer:
<u>Consider the following identity:</u>
- a³ - b³ = (a + b)(a² - ab + b²)
<u>Let a = 2, b = 1/2</u>
- (2 + 1/2)(2² - 2*1/2 + 1/2²) =
- 2³ - (1/2)³ =
- 8 - 1/8
Option A is correct as if we solve the equation We will find that the above equation can be compared to the standard quadratic equation i.e ax^2+bx+c=0
Here, we may use Geometric Progression
The sequence follows as:
27, 18,12,...
The first term (a)= 27
27/18 = 18/12
common ratio = 1.5
Let fourth term be x
Therefore , 12/x = 1.5
=> x= 12/1.5 = 8
