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Sergio039 [100]
3 years ago
11

Three different customers purchase kiwis The one customer pays 2.30 for 3 kiwis another 5.53 for 7 Kiwis and the other 8.69 for

11 KIWIS what is the cost per kiwi is it
$0.79

$6.90

$1.30

$0.59
Mathematics
1 answer:
grigory [225]3 years ago
8 0
The answer is $0.79 just divide the price with the number of kiwis 


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8. Archie plotted the points on the graph below to show how the amount he owes for tuition decreases as the number of tuition pa
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Step-by-step explanation:

5 0
2 years ago
What is the slope of this graph? <br>A. -1/3<br>B. -3<br>C. 3<br>D. 1/3​
Paul [167]
The answer is -3!


Hope this helps
3 0
3 years ago
Read 2 more answers
In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee
kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that x^{2} =pz

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and  Δ ADB in the attached file , ∠A is common in both triangles

                                                                     and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

\frac{x}{z}= \frac{p}{x}

Cross multiply

x^{2}=pz

Hence proved.


7 0
3 years ago
A machine is used to fill containers with a liquid product. Fill volume can be assumed to be normally distributed. A random samp
motikmotik

Answer:

There is no statistical evidence at 1% level to accept that    the mean net contents exceeds 12 oz.

Step-by-step explanation:

Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.

We find mean = 11.015

Sample std deviation = 3.157

a) H_0: \bar x= 12 oz\\H_a: \bar x >12

(Right tailed test)

Mean difference /std error = test statistic

\frac{11.015-12}{\frac{3.157}{\sqrt{10} } } \\=-0.99

p value =0.174

Since p >0.01, our alpha, fail to reject H0

Conclusion:

There is no statistical evidence at 1% level to accept that    the mean net contents exceeds 12 oz.

3 0
3 years ago
How do you do this???
wariber [46]

Answer:

idk im doing to same thing in class im confused too

Step-by-step explanation:

4 0
3 years ago
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