Ano po sagot dito hirap po kase eh

A charged object (like a balloon that's been rubbed on the wall) cant attract an object with a net neutral charge (neither posit

UNO [17]

Answer: A balloon is charged by a process of frictional charging and the object is getting charged by the process of induction.

Explanation:

When two bodies are rubbed against each other, charging by friction or rubbing occurs. The electropositive object loses electrons to electronegative object. Thus, when balloon is rubbed on a wall, it becomes charged.

The charged balloon is able to attract an uncharged object by inducing charge on it without the two objects touching each other. Electrostatic force acts between two charged objects. Charged balloon causes electrons to move at one end thereby inducing opposite charge in the object and thus, charged balloon is able to attract uncharged object.

4 0

4 years ago

A group 2 metal carbonate has a mass of 84 g/mol. Identify the group 2 metal X using its chemical formula.

zepelin [54]

Answer:

Magnesium

0.003mole

Explanation:

The problem here entails we find the metal in the carbonate.

For group 2 member, let the metal = X;

The carbonate is XCO₃;

If we sum the atomic mass of the elements in the metal carbonate, we should arrive at 84g/mol

Atomic mass of C = 12g/mol

O = 16g/mol

Atomic mass of X + 12 + 3(16) = 84

Atomic mass of X = 84 - 60 = 24g/mol

The element with atomic mass of 24g is Magnesium

B.

Number of moles in 0.3g of CaCO₃:

Molar mass of CaCO₃ = 40 + 12 + 3(16) = 100g/mol

Number of moles = $\frac{mass}{molar mass}$

Number of moles = $\frac{0.3}{100}$ = 0.003mole

7 0

3 years ago

What needed to be present in marine mud to form fossil fuels?

UkoKoshka [18]

When organisms and plants died and sank to the bottom of swamps and oceans, brown soil-like materials called peat are formed. Over millions of years, the peat became covered with sand, clay and other minerals and the peat is converted into layers of sedimentary rocks. After a long time, different type of fossil fuels are formed.

8 0

3 years ago

What is the sequence of coefficients that will balance the following decomposition reaction of dihydrogen monosulfide? H₂S ----&

RUDIKE [14]

8 S

In this case you must start balancing the sulfur to have 8 on each side of the reaction. So:

Answer:

Explanation:

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Then, taking into account all of the above, you can determine the amount of elements on each side of the equation:

Left side: 2 H and 1 S

Right side: 2 H and 8 S

In this case you must start balancing the sulfur to have 8 on each side of the reaction. So:

8 H₂S → H₂ + S₈

Now the amount of elements on each side of the equation:

Left side: 16 H and 8

Right side: 2 H and 8 S

Now you need to start balancing the hydrogen to get the same amount from each side of the reaction. So:

8 H₂S → 8 H₂ + S₈

Now the amount of elements on each side of the equation:

Left side: 16 H and 8

Right side: 16 H and 8 S

The balanced reaction is:

8 H₂S → 8 H₂ + S₈

3 0

3 years ago

Taryn has a 90-gram sample of ethanol, which has a specific heat of

Angelina_Jolie [31]

35 Celsius minus the average 20 Celsius. going to be 15. let me know if u need anything else.

7 0

3 years ago

Ano po sagot dito hirap po kase eh​

Ano po sagot dito hirap po kase eh