3. The masses of two gorillas are given below. A female gorila has a mass of

Explain to me how to do this please

nataly862011 [7]

You must first attach the problems with your question.

6 0

3 years ago

How to solve this? Please someone help

seropon [69]

Answer:

Step-by-step explanation:

So the sign means that y has to be less than or equal to x plus 9

if you wanted an answer an example could be

y = 1

x = 10

this works because if implemented into the equation

1 ≤ 10 + 9 which is true

4 0

3 years ago

Read 2 more answers

A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r

Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

$P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5$

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, $n(S)=6$

Now, probability of rolling a 3 is given as:

$P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}$

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

$P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083$

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0

3 years ago

What part of the expression below should be calculated first?

Lostsunrise [7]

C ,in the most parenthesis

8 0

3 years ago

Read 2 more answers

Consider the population consisting of all computers of a certain brand and model, and focus on whether a computer needs service

eimsori [14]

Answer and explanation:

A. What is the probability that more than half of the sample of 100 computers would need warranty service?

What is the probability that more than half of the sample of 100 computers would not need warranty service?

What is the probability that out of sample of 100 more than 20% would require warranty service?

B. If our sample of 100 computers of that brand and model reveals that 30 computers need warranty service, does this give a valid conclusion that all such computers in the population would require about 30% warranty service or less?

7 0

3 years ago