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yuradex [85]
4 years ago
13

Jika f(x) =

%201%7D%7D%20%20" id="TexFormula1" title=" = \sqrt{2} \times \sqrt{ {2}^{2x - 1}} " alt=" = \sqrt{2} \times \sqrt{ {2}^{2x - 1}} " align="absmiddle" class="latex-formula">
maka f(0) =
Mathematics
1 answer:
wel4 years ago
3 0

f(0) = \sqrt{2} · \sqrt{2^{2(0) - 1}}

= \sqrt{2} · \sqrt{2^{0 - 1}}

= \sqrt{2} · \sqrt{2^{- 1}}

= \sqrt{2} · \frac{1}{\sqrt{2}}

= \frac{\sqrt{2}}{\sqrt{2}}

= 1

Answer: 1

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A motor racing circuit has length 5 5/6 miles. A straight section of the circuit has 1 1/4 miles. What fraction of the circuit i
aleksklad [387]

Answer:

3/14

Step-by-step explanation:

1 1/4 can be written as 5/4

5 5/6 can be written as 35/6

so divide (5/4)/(35/6)

= (5/4)*(6/35)

=(1/4)*(6/7)

=6/28

simplified = 3/14

4 0
3 years ago
What is the product of (1.9*10^-3)(2*10^4)
RoseWind [281]

Answer:

to solve use the distributive property and multiply

Step-by-step explanation:

I'm sorry I do not have the product

4 0
3 years ago
Read 2 more answers
2. A restaurant employs five people. The two cooks work 36 hours
Cloud [144]

Answer:

Total amount = R5112

Step-by-step explanation:

Let the cooks be C.

Let the waiters be W.

Given the following data;

Number of cooks, C = 2

Number of waiters, W = 3

a. To find the amount earned by each cook;

C = 36 * R36 = R1296

b. To find the amount earned by each waiter;

W = 30 * R28 = R840

c. To find the total amount earned by the employees;

Total amount = 2C + 3W

Total amount = 2(1296) + 3(840)

Total amount = 2592 + 2520

Total amount = R5112

4 0
3 years ago
In a sample of 41 temperature readings taken from the freezer of a restaurant, the mean is 29.7 degrees and the population stand
yKpoI14uk [10]

Answer: =(29.1596\text{ degrees},\ 30.2404\text{ degrees})

Step-by-step explanation:

Given: Sample size: n = 41

Sample mean \overline{x}= 29.7 degrees

Population standard deviation \sigma=2.7 degrees

Confidence level (c) =  80% =0.80

Significance level (a) = 1- c = 1-0.80 = 0.20

z-score for 80% confidence level : z = 1.2816   [from z-table]

Confidence level for population mean :-

\overline{x}\pm z\dfrac{\sigma}{\sqrt{n}}

=29.7\pm ( 1.2816)\dfrac{2.7}{\sqrt{41}}

=29.7\pm ( 1.2816)\dfrac{2.7}{6.403124}

=29.7\pm ( 1.2816)(0.42167)

=29.7\pm 0.5404

=(29.7-0.5404,\ 29.7+0.5404)

=(29.1596,\ 30.2404)

Hence, 80% confidence interval for the temperatures in the freezer =(29.1596\text{ degrees},\ 30.2404\text{ degrees})

7 0
3 years ago
How do you solve this problem?
umka21 [38]
The answer to your math question is x=5
7 0
2 years ago
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