The sum of two numbers is 13 more than twice the first number:
x + y = 2x +13
x - y = y - 14
solve the system of equations:
x - (x + 13) = (x +13) - 14
x = -12
y = 1
Answer:
three-forth minus one-fifth times four
Step-by-step explanation:
Look at the graph below carefully
Observe the results of shifting ={2}^{x}f(x)=2x
vertically:
The domain, (−∞,∞) remains unchanged.
When the function is shifted up 3 units to ={2}^{x}+3g(x)=2x +3:
The y-intercept shifts up 3 units to (0,4).
The asymptote shifts up 3 units to y=3y=3.
The range becomes (3,∞).
When the function is shifted down 3 units to ={2}^{x}-3h(x)=2 x −3:
The y-intercept shifts down 3 units to (0,−2).
The asymptote also shifts down 3 units to y=-3y=−3.
The range becomes (−3,∞).