All categories

2 years ago

Write 9 as a product of two primes.

Mathematics

2 answers:

-BARSIC- [3]2 years ago

8 0

Step-by-step explanation:

so we start using repeated division to find 9 as a product of primes.

First divide 9 by the smallest prime factor it has.

9/3=3

Next, divide the result (3) by the smallest prime factor it has.

3/3=1

Once you reach 1, which we just did, you have finished.

Now collect all the results you have.

3x3

There you go, 9=3x3, as a product of primes.

or 3^2, if you want to write it in index notation.

This works for any integer.

NARA [144]2 years ago

4 0

Step-by-step explanation:

9 can be written as a product of 3 and 3

9=3×3 ( because 3 is a prime no. as it has two different factors ,i.e. 3 and 1)

You might be interested in

Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)

UkoKoshka [18]

Since the limit becomes the undetermined form

$\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}$

it means that both polynomials have a root at $x=1$ . So, we can fact both numerator and denominator:

$x^3-2x^2+3x-2 = (x-1)(x^2-x+2)$

$2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)$

So, the fraction becomes

$\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}$

Now, as x approaches 1, you have no problems anymore:

$\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}$

4 0

2 years ago

You do not need to be concerned if there are limits on what a company will pay for a service of medical or dental procedures.

riadik2000 [5.3K]

False because you should always make sure a company has medical and detal procedures

8 0

3 years ago

Which lines in the graph have a slope greater than 1 but less than 2?

lapo4ka [179]

Answer:

Lines 3 and 4

Step-by-step explanation:

Let's examine the slope of each of the given lines to have the exact value and be able to answer the question. We use the definition of: $slope=\frac{rise}{run}$

Line 1: $slope=\frac{rise}{run}=\frac{6}{2} = 3$

Line 2: $slope=\frac{rise}{run}=\frac{6}{3} = 2$

Line 3: $slope=\frac{rise}{run}=\frac{6}{4} = 1.5$

Line 4: $slope=\frac{rise}{run}=\frac{6}{5} = 1.2$

Line 5: $slope=\frac{rise}{run}=\frac{6}{6} = 1$

Therefore the lines that have slope strictly greater than 1 and less than 2 are:

Lines 3 and 4

3 0

2 years ago

Read 2 more answers

What is the perimeter of a quadrilateral with vertices at (3,-6),(8,-6),(3,-4), and (8,-4)

Eduardwww [97]

Answer:

im sorry i dont know but this is for a challenge

Step-by-step explanation:

3 0

2 years ago

Functions f(x) and g(x) are shown below:

kondor19780726 [428]

We look for the minimum of each function.
For f (x) = 3x2 + 12x + 16:
We derive the function:
f '(x) = 6x + 12
We match zero:
6x + 12 = 0
We clear the value of x:
x = -12/6
x = -2
We substitute the value of x in the equation:
f (-2) = 3 * (- 2) ^ 2 + 12 * (- 2) + 16
f (-2) = 4
For g (x) = 2sin(x-pi):
From the graph we observe that the minimum value of the function is:
y = -2
Answer:
A function that has the smallest minimum y-value is:
y = -2

4 0

3 years ago