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4vir4ik [10]
3 years ago
11

ASAP someone please simply two exponents

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:

1.) m^{15}

2.) =\frac{1}{y^{15}}

Give me a comment if you want the explanation.

1.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(m^3\right)^5=m^{3\cdot \:5}

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:5=15

=m^{15}

2.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(y^{-3}\right)^5=y^{-3\cdot \:5}

=y^{-3\cdot \:5}

=y^{-15}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

=\frac{1}{y^{15}}

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Answer:

22% reduction

Step-by-step explanation:

Find the percent decrease by dividing the difference in amounts by the original amount.

Find the difference:

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Divide this by the original amount:

25/115

= 0.217

So, the percent decrease is 21.7%. Round this to the nearest whole percentage:

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6 0
3 years ago
D-10-2d+7=8+d-10-3d
TEA [102]

Solution,solve\:for\:d,\:d-10-2d+7=8+d-10-3d\quad :\quad d=1

Steps:

d-10-2d+7=8+d-10-3d

\mathrm{Subtract\:}d-10\mathrm{\:from\:both\:sides},\\d-10-2d+7-\left(d-10\right)=8+d-10-3d-\left(d-10\right)

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\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides},\\-2d+7-7=8-3d-7

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\mathrm{Add\:}3d\mathrm{\:to\:both\:sides},\\-2d+3d=-3d+1+3d

\mathrm{Simplify},\\d=1

\mathrm{The\:Correct\:Answer\:is\:d=1}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

4 0
4 years ago
Express answer in exact form.
Andreyy89
Hello,
Please, see the attached file.
Thanks.

6 0
4 years ago
Find the factors of following:<br>(i) 8x^2 yy
g100num [7]

Answer:

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Answer:

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