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4vir4ik [10]
3 years ago
11

ASAP someone please simply two exponents

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:

1.) m^{15}

2.) =\frac{1}{y^{15}}

Give me a comment if you want the explanation.

1.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(m^3\right)^5=m^{3\cdot \:5}

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:5=15

=m^{15}

2.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(y^{-3}\right)^5=y^{-3\cdot \:5}

=y^{-3\cdot \:5}

=y^{-15}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

=\frac{1}{y^{15}}

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d<em>y</em>/d<em>x</em> = -cos(<em>π</em>/3) / sin(<em>π</em>/3)

d<em>y</em>/d<em>x</em> = -cot(<em>π</em>/3) = -1/√3

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2 years ago
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