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never [62]
3 years ago
9

-1 1/4 + 1/2 A)-1 3/4 B)-1 1/2 C)-3/4 D)-1/2

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0

Answer:

<em>Well, Your best answer will be is </em><em>B. -1 1/2. </em>

<em>Hope That Helps!</em>

^{Itsbrazts}

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Evaluate the expression 3^4 ÷ (14 − 5) × 2.
gavmur [86]

Answer:

18

Step-by-step explanation:

3^4=9*9=81

14-5=9

81/9=9

9*2=18

8 0
3 years ago
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Fifteen times the square of a non-zero number is equal to 12 times the number. whats the number?
Fofino [41]
15x^2 = 12x
divide each side by x
15x = 12
now divide each side by 15
x = 12/15 or 4/5 which is also 0.8
4 0
3 years ago
Please help me I don't know what this is I will mark brainliest
lyudmila [28]

Answer:

improper fractions are mixed numbers that can be multiplied by bottom to top like 2/4 x 4/5 so is 2 and 4 from 2/4 and 4/5 you can also do bottom to top like 2 x 5=10 and 4 x 4= 16 now you can add 10 + 16=26

7 0
1 year ago
Jess wrote Amanda a check for $358.36, and Amanda deposited the check into her checking account. Where was Amanda's signature? A
Alex777 [14]
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6 0
2 years ago
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Hannah has information about an object in circular orbit around Earth. MEarth = 6. 0 × 1024 kg G = 6. 67 × 10–11 StartFraction m
castortr0y [4]

In order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

<h3>What is the tangential speed of the object?</h3>

The tangential speed of an object is the linear component of the speed, which is moving in a circular path.

In terms of  the gravitation constant, the tangential speed can be given as,

v=\sqrt{\dfrac{Gm}{r}}

Here, {<em>G</em>} is the gravitation constant, (<em>m</em>) is the mass and (<em>r</em>) is the radius.

Hannah has information about an object in circular orbit around Earth.

The mass of the earth is.

m_E=6. 0 \times10^{24} kg

The value of gravitational constant is,

G=6. 67\times 10{-11}\rm Nm^2/kg^2

The radius of the earth is,

r_E=6. 0 \times 10^6 \rm m

Here, only the distance of the orbiting object to Earth is need to find the tangential speed of the object.

Hence, in order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

Learn more about the tangential speed here;

brainly.com/question/4933588

7 0
2 years ago
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