Answer:
3 beause when you dividend it -5.6+4(3) .
I only got 22-25 done cause its been a long time since ive done these so i don't remember how to do the first two ):
I think its c
Step-by-step explanation:
Answer:
P(A∪B) = 1/3
Step-by-step explanation:
Red Garments = 1 red shirt + 1 red hat + 1 red pairs of pants
Total Red Garments = 3
Green Garments = 1 green shirt + 1 green scarf + 1 green pairs of pants
Total Green Garments = 3
The total number of garments = Total Red Garments + Total Green Garments:
3 + 3 = 6
Let A be the event that he selects a green garment
P(A) = Number of required outcomes/Total number of possible outcomes
P(A) = 3/6
Let B be the event that he chooses a scarf
P(B) = 1/6
The objective here is to determine P(A or B) = P(A∪B)
Using the probability set notation theory:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∩B) = Probability that a green pair of pant is chosen = P(A) - P(B)
= 3/6-1/6
= 2/6
P(A∪B) = 1/2 + 1/6 - 2/6
P(A∪B) = 2/6
P(A∪B) = 1/3
An equilateral shape is a shape that has all congruent sides.
<em>Sandy has a greater probability of selecting an equilateral shape</em>
Given
Sandy: <em>Equilateral triangle, Rhombus, and Regular hexagon</em>
Robert: <em>Scalene triangle, Kite, Isosceles trapezoid, Non-special quadrilateral, and Obtuse isosceles triangle</em>
All three shapes in Sandy's shape bucket are equilateral.
So, the probability that Sandy picks an equilateral shape is 1
All five shapes in Robert's shape bucket are non-equilateral.
So, the probability that Robert picks an equilateral shape is 0
By comparing the probabilities:
<em>1 is greater than 0</em>
Hence, Sandy is more likely to pick an equilateral shape than Robert.
Read more about probabilities at:
brainly.com/question/24297863
