Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
The 3 in 350 is in the hundreds place. the 3 in 403 is in the ones place
There are to be exact only 2 ways to answer this equation because of the way math was made.
Answer:
+ 12
Step-by-step explanation:
8 - (- 4) = 8 + 4 = 12
4n - 3 = 4 * 10 - 3 = 40 - 3 = 37
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