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Tcecarenko [31]
3 years ago
10

Cynthia Besch wants to buy a rug for a room that is 20 feet wide and 34 feet long. She wants to leave a uniform strip of floor a

round the rug. She can afford to buy 392 square feet of carpeting. What dimensions should the rug​ have?
Mathematics
1 answer:
Leto [7]3 years ago
7 0

Answer:

b

Step-by-step explanation:

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I need help with this
Assoli18 [71]
On a given line, (on one side) there are a total of 180°

if one line in Problem #3 is bisected by a line, with one half X and the other 120°,

do 180° (the total) minus 120° which=60°

now the hard part, that line that bisected the first line is bisecting a line that is parallel to your second line, the one with <5 and <6

this means that the big angle formed in the first one with 120° is the same angle as in the second line, leaving <5 as 120°
which means <6 is 60°, like in the top part of the problem. You're basically flipping the top line upside down, I hope it helps.
7 0
4 years ago
Triangle JKL is a right triangle. What is the length of JK?
kari74 [83]

I would go with

G: 4 cm

Or

J: 8 cm

Let me know if you get it correct! :)

8 0
3 years ago
Read 2 more answers
Can someone please teach me how to do this? You can please do like 2 questions and please explain exactly how you got the answer
spayn [35]

All of these questions require one thing: trigonometric functions.

There are 3 main trigonometric functions, which can only be used on right triangles: sine, cosine, and tangent.

Sine = opposite / hypotenuse

Cosine = adjacent / hypotenuse

Tangent = opposite / adjacent

When trying to figure out what function to use, we always start by looking from the angle. Take problem a, for example. Looking from angle E, of which the value is not given, we have the side opposite and the side adjacent. Therefore, we should use the tangent function.

---The hypotenuse is always the longest side of the triangle. It is never considered the opposite or adjacent side.

Let's set up our function with the given information from problem a.

tan(x) = 9.7 / 5.2

---The tangent of an unknown angle is equal to the quotient of the opposite side and the adjacent side.

Now, solving for the value of x will require a calculator. We'll need to use what's called an inverse trigonometric function. Most calculators have these directly above the regular trigonometric functions, and the inverse functions are accessed using a "second" key.

---Ensure that your calculator is in degrees, not radians!

x = tan^-1(9.7 / 5.2)

x = 61.805 = 62 degrees

Next, let's take a look at problem b. This time, we're solving for a side length instead of an angle. But, we're still going to start by looking from our angle.


Looking from the 38 degree angle, we are given the adjacent side and an unknown hypotenuse. Therefore, we should use the cosine function.

cosine(38) = 53.1 / r

---The cosine of a 38 degree angle is equal to the quotient of 53.1 and an unknown hypotenuse, r.

Use your algebra skills to isolate the variable r.

r * cosine(38) = 53.1

r = 53.1 / cosine(38)

---From here, all you need to do is plug this into your calculator. Since we are solving for a side length (and given an angle), we are just using the regular trigonometric function buttons on the calculator.

r = 67.385 = 67.4 units

Hope this helps!

4 0
2 years ago
Write the sum of 120 36 as the product of their gf and another sum
r-ruslan [8.4K]
120 + 36 = 12(10 + 3)
5 0
3 years ago
Jon is launching rockets in an open field. The path of the rocket can be modeled by the quadratic function h(t) = -16t^2 + 96t,
IrinaVladis [17]
It will reach 80 feet for the second time after 5 seconds.

We set the equation equal to 80 feet:
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When solving quadratics, we want it equal to 0, so we subtract 80 from both sides:
80-80= -16t² + 96t - 80
0= -16t² + 96t - 80

We use the quadratic formula to solve:
t=\frac{-96\pm \sqrt{96^2-4(-16)(-80)}}{2(-16)}&#10;\\&#10;\\t=\frac{-96\pm \sqrt{9216-5120}}{-32}&#10;\\&#10;\\t=\frac{-96\pm \sqrt{4096}}{-32}&#10;\\&#10;\\t=\frac{-96\pm 64}{-32}&#10;\\&#10;\\t=\frac{-96+64}{-32} \text{ or } 0=\frac{-96-64}{-32}&#10;\\&#10;\\t=1 \text{ or } t=5
4 0
4 years ago
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