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Nutka1998 [239]
3 years ago
14

Richard Baker drove to Lawrenceville, GA. In 3 hours. The distance is 196 miles. About how many miles per hour did he travel?

Mathematics
2 answers:
Sonbull [250]3 years ago
4 0
196 divided by 3 equals about 65.3 so Richard traveled about 65 miles per hour
myrzilka [38]3 years ago
3 0
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Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention
Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

a=\frac{d^2s}{dt^2}

Differentiate the position vector with respect to t.

\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}

Differentiate both sides of the obtained equation with respect to t.

\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}

The initial position is obtained at t=0. Substitute t=0 in the given position function.

\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}

8 0
1 year ago
What is matrix X if 0.5X=A? Matrix A=[6 -12 4 6].
vladimir1956 [14]

Answer:

See attachment

Step-by-step explanation:

The given matrix equation is:

0.5X = A.

To find Matrix X, we need to multiply both sides of the equation by 2 to obtain:

2 \times 0.5X =2 \times  A

This simplifies to;

X = 2A

By scalar multiplication, we multiply each entry in the matrix A by to 2 to obtain matrix X.

6 0
3 years ago
“a number greater than or to -3”
mars1129 [50]

Answer:

5

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A grid is 10 squares high and 10 squares wide. The distance between each grid square is 3 feet. The triangular viewing area of c
meriva

Answer:

1) 8

2) 450 ft^2

Step-by-step explanation:

Each triangle takes half a square worth of space, so if you add up 2 triangles for 1 square that is 1/4 of the area, multiply that by 4 and you get 8 cameras.

The left over space in the store is the same amount of space as all the cameras space added together since each camera takes up half a square. That way 4 cameras(each 112.5 ft^2 each) equals 1/2 of the room which added together is 450 ft^2, the other half would be the left over space, 450 ft^2.

7 0
2 years ago
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The area of a parallelogram is 6 ft' and the height is 3 ft. Find the length of the corresponding base.
Reil [10]
Just do 6/3 because you have the area and one length, just divide the area by the height you have.
6 0
3 years ago
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