Ask question

Ask question

All categories

4 years ago

6

Question 4: The storage in a reach of a river at a point in time is 255 m3 (meters cubed) . Determine the average rate of inflow

(m3 s -1 ) to the river reach required to raise the storage to 325 m 3 if the average outflow was 0.30 m3s -1 (meters cubed/ second) over a 1-hour period.

1 answer:

irakobra [83]4 years ago

8 0

Answer:

0.319 m³/s

Step-by-step explanation:

Data provided:

Initial volume in the river = 255 m³

Final volume required in the storage = 325 m³

Average outflow = 0.30 m³/s

Duration for raising the level = 1 hour = 3600 seconds

Now,

The actual volume required to raise the volume to 325 m³

= Final volume - Initial volume

= 325 m³ - 255 m³

= 70 m³

also,

the amount of outflow in 1 hour = Average rate of outflow × Time

= 0.30 m³/s × 3600 s

= 1080 m³

Therefore,

the total volume required = 1080 m³ + 70 m³ = 1150 m³

Now,

the average rate of inflow required = $\frac{\textup{Total volume required}}{\textup{Time}}$

= $\frac{\textup{1150}}{\textup{3600}}$

= 0.319 m³/s

You might be interested in

A hockey game is 60 minutes. Colin plays 12 minutes. Which ratio represents Colin’s playing time compared to the total number of

drek231 [11]

Answer:

60 t0 12, or 1:5, or 1/5

Step-by-step explanation:

6 0

3 years ago

The length of a rectangle is 3 times the length of a

laila [671]

$larger\ rectangles:3l\ \times\ w\\\\smaller\ rectangles:l\ \times\ w\\\\A_{larger}=kA=3lw\\\\A_{smaller}=A=lw\\\\\frac{A_{larger}}{A_{smaller}}=\frac{kA}{A}=k\\\\k=\frac{3lw}{lw}=3\\\\Answer:J.$

4 0

3 years ago

Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,

creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by $a_0=0$ $a_n=a_{n-1}+3n-1$

To find : Write out the first 5 terms of this sequence ?

Solution :

$a_n=a_{n-1}+3n-1$ and $a_0=0$

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

$a_1=a_{1-1}+3(1)-1$

$a_1=a_{0}+3-1$

$a_1=0+2$

$a_1=2$

For n=2,

$a_2=a_{2-1}+3(2)-1$

$a_2=a_{1}+6-1$

$a_2=2+5$

$a_2=7$

For n=3,

$a_3=a_{3-1}+3(3)-1$

$a_3=a_{2}+9-1$

$a_3=7+8$

$a_3=15$

For n=4,

$a_4=a_{4-1}+3(4)-1$

$a_4=a_{3}+12-1$

$a_4=15+11$

$a_4=26$

For n=5,

$a_5=a_{5-1}+3(5)-1$

$a_5=a_{4}+15-1$

$a_5=26+14$

$a_5=40$

The first 5 terms of the sequence is 2,7,15,26,40.

5 0

3 years ago

4/5 divided by 1/10?

Evgesh-ka [11]

Answer:

the answer to the question is 8

6 0

3 years ago

Read 2 more answers

7m2 + 3m + 4m2<br> What is the answer to this

mylen [45]

I’m assuming the 2’s are supposed to be exponents so you’re gonna to combine 7m^2 and 4m^2 to get 11m^2 so you’re answer would be

11m2+3m

You dint know the value of M so you can’t solve it, especially because there’s no equal sign with a number or expression/equation after it.

8 0

3 years ago