That’s really cool but thanks for free pointss <333
Answer:
a. no b. 40.05
Step-by-step explanation:
a. to figure out the number of goals per game you have to divide the total amount of goals by the number of games:
last season: 41 ÷ 15 = 2.73
this season: 24 ÷ 9 = 2.67
as you can see the answer to the last season equation is higher than the this season meaning the player scored more goals last season.
b. we already know that the amount of games the player won each game (all of them supposedly being exactly even) is 2.67. so what we have to do is multiply it by 15 the supposed number of games the player is playing this season to get the total number of goals they will get for the entire season:
2.67 x 15 = 40.05 = the prediction of the total goals of the player
Answer:
(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0
(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0
Step-by-step explanation:
(a) when i = 2, the expected number of played games will be:
E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] = 4p²-4p+2-6p²+6p = -2p²+2p+2.
If p = 1/2, then:
d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.
(b) when i = 3;
E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]
Simplification and rearrangement lead to:
E(X) = 6p⁴-12p³+3p²+3p+3
if p = 1/2, then:
d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10
Therefore, E(X) is maximized.
Answer:
19
Step-by-step explanation:
Add from numbers 14-20
