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2 years ago

The solutions of the equation x^2-6x+4=0

Mathematics

1 answer:

lesya692 [45]2 years ago

6 0

Answer:

you have 2 options!!!

Step-by-step explanation:

hoped I helped!

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3 years ago

Which of the following is a like radical to RootIndex 3 StartRoot 6 x squared EndRoot? x (RootIndex 3 StartRoot 6 x EndRoot) 6 (

aliya0001 [1]

Answer:

4 (RootIndex 3 StartRoot 6 x squared EndRoot) = 4 $\sqrt[3]{6x^2}$

Step-by-step explanation:

<em>Added radical forms to the question for better visibility.</em>

Which of the following is a like radical to RootIndex 3 StartRoot 6 x squared EndRoot = $\sqrt[3]{6x^2}$ ?

x (RootIndex 3 StartRoot 6 x EndRoot) = x $\sqrt[3]{6x}$
6 (RootIndex 3 StartRoot x squared EndRoot) = 6 $\sqrt[3]{x^2}$
4 (RootIndex 3 StartRoot 6 x squared EndRoot) = 4 $\sqrt[3]{6x^2}$
x (RootIndex 3 StartRoot 6 EndRoot) = x $\sqrt[3]{6}$

<h3>Solution</h3>

<em>Like radicals are radicals that have the same root number and expression under the root.</em>

1) x $\sqrt[3]{6x}$ = $\sqrt[3]{6x^4}$

No, incorrect

2) 6 $\sqrt[3]{x^2}$ = $\sqrt[3]{6^3x}$

No, incorrect

3) 4 $\sqrt[3]{6x^2}$

Yes, correct

4) x $\sqrt[3]{6}$ = $\sqrt[3]{6x^3}$

No, incorrect

Compared with the given radical, we can see from the given choices only 3rd choice is like radical with $\sqrt[3]{6x^2}$

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3 years ago

(8c2-2c) + (2c2+3c) in standard form

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

hello :

(8c²-2c) + (2c²+3c)= (8c²+3c²)+(3c-2c) =11c²+c .....standard form

5 0

3 years ago