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Misha Larkins [42]
3 years ago
11

Based on these segment lengths, which group of segments can form a triangle?

Mathematics
1 answer:
REY [17]3 years ago
8 0

Answer:

20,7,13. are the most correct for a triangular shape

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Simplify the expression below. (2n/6n+4)(3n+2/3n-2)
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Answer:

\frac{n}{3n-2}

Step-by-step explanation:

Given the expression:

\frac{2n}{(6n+4)} \cdot \frac{3n+2}{3n-2}

Using the distributive property: a \cdot (b+c) =a\cdot b+a\cdot c

\frac{2n}{2(3n+2)} \cdot \frac{3n+2}{3n-2}

Simplify:

\frac{2n}{2} \cdot \frac{1}{3n-2}

Simplify:

\frac{n}{3n-2}

Therefore, the simplified given expression is, \frac{n}{3n-2}

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yawa3891 [41]

An equation is formed of two equal expressions. The equation of function g(x) in terms of f(x) is g(x) = -3[f(x)].

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The given graph is the graph of an exponential function, the general equation of an exponential function is given by the y=aeᵇˣ. To get the function f(x) and g(x), you need to substitute the points in the given function and produce the equation of each function.

The equation for f(x) from the given graph can be written as,

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Now, similarly from the graph the function of g(x) can be written as,

g(x)=-3e^{(\ln2)x}+6

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g(x) = -3[f(x)]

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kumpel [21]

Answer:

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