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Lelu [443]
3 years ago
5

A carton has a length of fraction 2 and 2 over 3 feet, width of fraction 1 and 1 over 3 feet, and height of fraction 1 and 1 ove

r 2 feet. What is the volume of the carton?
Mathematics
1 answer:
astraxan [27]3 years ago
7 0
Writing this problem in symbols instead of in words greatly simplifies it:

(2  2/3) * (1  1/5) * (1  1/2)

Write each quantity (inside each set of parentheses) as an improper fraction:

(8/3) * (6/5) * (3/2)

Now multiply the numerators thru:  8*6*3 / 3*5*2

Notice that we can reduce this by dividing the 8 by the 2 and dividing the 6 by the 3:                                                4*3*3             36
                                                        ----------  =  -----------
                                                             5                  5
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antiseptic1488 [7]

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PLEASE HELP!
makvit [3.9K]

Answer:

Step-by-step explanation:

<h2>Cone:</h2>

    diameter = 12 cm

                  r =  12 ÷ 2 = 6 cm

                 h = 6 cm

      \sf \boxed{\text{\bf Volume of cone = $\dfrac{1}{3} \pi r^2h$ }}

                                    \sf = \dfrac{1}{3}*3.14*6*6*6\\\\ = 226.08 \ cm^3

To find the surface area, we need to find the slant 'l'

       \sf l = \sqrt{h^2+r^2}\\\\       =\sqrt{6^2+6^2}\\\\        = \sqrt{36+36}\\\\ =\sqrt{72}\\\\= 8.49 \ cm

       \sf \boxed{\text{\bf Total surface area of cone = $\pi r(r+l)$}}

                                                         = 3.14 * 6 * (6 + 8.49)

                                                        = 3.14 * 6 * 14.49

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8 0
2 years ago
First term is is 22 and the common difference is -13
bonufazy [111]

Answer:

a_{n} = 35 - 13n

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Assuming you require the n th term formula

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n- 1)d

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Here a₁ = 22 and d = - 13, thus

a_{n} = 22 - 13(n - 1) = 22 - 13n + 13 = 35 - 13n

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liraira [26]
I think it would be 120
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