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3 years ago

Which equation has a solution of n =3.3

Mathematics

1 answer:

butalik [34]3 years ago

5 0

Answer:

5.2 + n = 8.5

Step-by-step explanation:

n would equal 3.3

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Find the probability of not rolling prime numbers on both dice

gladu [14]

Here’s the prime numbers on one dice: 2 3 5, so 3/6. If you have two die then your answer is 6/12. You have a 50 percent chance of not rolling prime numbers on both.

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3 years ago

Find the equation of the axis of symmetry and the coordinates of vertex of the functions =2x^2+4x-3

SVEN [57.7K]

Hello,

Find the equation of the axis of symmetry is like find the maximum or minimum point of this function.

$f(x)=2x^2+4x-3\\\\\alpha=-\dfrac{b}{2a}=-\dfrac{4}{4}=-1\\\\$

The equation of the axis of symmetry is then : $x=-1$

$\beta=f(\alpha)=2(-1)^2+4(-1)-3=2-4-3=-5$

Coordinates of vertex : $(\alpha,\beta)=(-1;-5)$

8 0

3 years ago

Pine St. and main st. Are?

garik1379 [7]

Answer:

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Step-by-step explanation:

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3 years ago

The city has an average of 13 days of rainfall for April.

zhenek [66]

Using the Poisson distribution, we have that:

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

For this problem, the mean is given as follows:

$\mu = 13$

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859$

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0$

$P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003$

$P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019$

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

6 0

2 years ago

Find the perimeter for the rectangle A=2xy mi^2

Stels [109]

-2mxy is what I found

7 0

3 years ago