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butalik [34]
3 years ago
11

Need number 11 and 10 all parts

Mathematics
1 answer:
klio [65]3 years ago
7 0
Nobody’s gonna do all parts for only 5 points
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Write 25 ) 10^6 in standard form
klemol [59]
Your answer is: 25,000,000
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
sweet-ann [11.9K]

Answer:  $25,500

<u>Step-by-step explanation:</u>

The given sequence {1300, 1300+150, ... } provides the following information:

  • the first term (a₁) = 1300
  • the difference (d) = 150

We can use the information above to find the explicit rule of the sequence:

a_n=a_1+d(n-1)\\.\quad =1300+150(n-1)\\.\quad =1300+150n-150\\.\quad =1150+150n

We can use the explicit rule to find the 12th term (a₁₂)

a_n=1150+150n\\a_{12}=1150+150(12)\\.\quad =1150+1800\\.\quad =2950

Next, we can input the first and last term of the sequence into the Sum formula:

S_n=\dfrac{a_1+a_n}{2}\times n\\\\S_{12}=\dfrac{a_1+a_{12}}{2}\times 12\\\\.\quad =\dfrac{1300+2950}{2}\times 12\\\\.\quad =\dfrac{4250}{2}\times 12\\\\.\quad =2125\times 12\\\\.\quad =25,500

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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