All categories

3 years ago

A sample of a hydrocarbon is found to contain 7.48g carbon and 2.52g hydrogen. What is the empirical

Chemistry

1 answer:

Aliun [14]3 years ago

6 0

Answer:

CH₄

Explanation:

To determine the empirical formula of the hydrocarbon, we need to follow a series of steps.

Step 1: Determine the mass of the compound

The mass of the compound is equal to the sum of the masses of the elements that form it.

m(CxHy) = mC + mH = 7.48 g + 2.52 g = 10.00 g

Step 2: Calculate the percent by mass of each element

%C = mC / mCxHy × 100% = 7.48 g / 10.00 g × 100% = 74.8%

%H = mH / mCxHy × 100% = 2.52 g / 10.00 g × 100% = 25.2%

Step 3: Divide each percentage by the atomic mass of the element

C: 74.8/12.01 = 6.23

H: 25.2/1.01 = 24.95

Step 4: Divide both numbers by the smallest one, i.e. 6.23

C: 6.23/6.23 = 1

H: 24.95/6.23 ≈ 4

The empirical formula of the hydrocarbon is CH₄.

You might be interested in

4. If the DNA nitrogen bases were TACCGGAT, how would the other half of

Elena L [17]

Answer:

<u>ATGGCCTA</u>

Explanation:

For this we have to keep in mind that we have a <u>specific relationship between the nitrogen bases</u>:

-) <u>When we have a T (thymine) we will have a bond with A (adenine) and viceversa</u>.

-) <u>When we have C (Cytosine) we will have a bond with G (Guanine) and viceversa</u>.

Therefore if we have: TACCGGAT. We have to put the corresponding nitrogen base, so:

TACCGGAT

<u>ATGGCCTA</u>

<u></u>

I hope it helps!

6 0

3 years ago

If you made a three-dimensional model of an atom and its nucleus, how would you represent the atom? 7th grade

Gemiola [76]

Answer:

it shows the breakdown of the atom

Explanation:

it will show it molecularly

7 0

3 years ago

Does any solid Ag₂CrO₄ form when 2.7x10⁻⁵g of AgNO₃ is dissolved in 15.0 mL of 4.0x10⁻⁴MK₂CrO₄?

e-lub [12.9K]

Molarity of Ag+ is less than the molar solubility thus ppt will not occur.

Balanced reaction-:

Moles of AgNO3=mass(g)molar mass (g/mol) =2.7×10−5g / 169.86 gmol

=1.589⋅10^−7 mol

Molarity of Ag+=moles of solute(L)=1.589⋅10−7 mol0.015 L=1.059⋅10−5M

Ksp of Ag2CrO4

=[Ag+]2[CrO42−]

1.2⋅10−12=[2s]2[s]

4s3=1.2⋅10−12

s=6.69⋅10−5 M

Molarity of Ag+ is less than the molar solubility thus ppt will not occur.

<h3>What is the molarity calculation formula?</h3>

The volume of solvent required to dissolve the provided solute is multiplied by the ratio of the moles of the solute whose molarity has to be computed. (M=frac{n}{V}) The molality of the solution that needs to be computed in this case is M. n is the solute's molecular weight in moles.

Learn more about Molarity:

brainly.com/question/8732513

#SPJ4

3 0

1 year ago

In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 19.6 grams of z

storchak [24]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

<u>Step 1: </u>Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc T1= 98.37 °C

Initial temperature of water T1= 24.16 °C

Final temperature of water (and zinc) T2 = 25.70 °C

Specific heat of water = 4.184 J/g°C

<u>Step 2: </u>Calculate Specific heat of zinc

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

Qzinc = -Qwater

m(zinc)*c(zinc)* ΔT(zinc) = - m(water)*c(water)* ΔT(water)

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

4 0

3 years ago

The invisible spectrum contains all the colors of the rainbow.<br> A.)True<br> B.)False

frosja888 [35]

Answer:

False

Explanation:

We can see the colors of the rainbow, therefore they are visible.

3 0

3 years ago

Read 2 more answers