Explanation:
The given reaction is as follows.
Hence, number of moles of NaOH are as follows.
n = 
= 0.005 mol
After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.
n = 
= 0.0025 mol
According to ICE table,
Initial: 0.005 mol 0.0025 mol 0 0
Change: -0.0025 mol -0.0025 mol +0.0025 mol
Equibm: 0.0025 mol 0 0.0025 mol
Hence, concentrations of HA and NaA are calculated as follows.
[HA] = 
[NaA] =
![[A^{-}] = [NaA] = \frac{0.0025 mol}{V}](https://tex.z-dn.net/?f=%5BA%5E%7B-%7D%5D%20%3D%20%5BNaA%5D%20%3D%20%5Cfrac%7B0.0025%20mol%7D%7BV%7D)
Now, we will calculate the 
value as follows.
pH = 
![pK_{a} = pH - log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%3D%20pH%20-%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
= 
= 3.42
Thus, we can conclude that of the weak acid is 3.42.
Particles of gas are more scarcely placed as compared to that of liquid.
the intermolecular forces will be less in gaseous state and hence is less stable
Answer:
The combination of oxygen with other substances to produce new chemical products is called <u>Oxidation</u>.
Explanation:
Oxidation reactions are defined as,
In terms of Inorganic chemistry:
(i) <u>Removal of Electrons: </u>
Example: Mg → Mg²⁺ + 2 e⁻
(ii) <u>Addition of Oxygen:</u>
Example: 2 Mg + O₂ → 2 MgO
In terms of Organic chemistry:
(i) <u>Addition of Electrons: </u>
Example: Cl₂ + 2 e⁻ → 2 Cl⁻
(ii) <u>Addition of Hydrogen:</u>
Example: H₂CCH₂ + H₂ → H₃CCH₃
New, stronger bacteria have evolved that are resistant to antibiotics.
Answer:
a metal spoon left in boiling water
Explanation:
