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Shkiper50 [21]
3 years ago
9

Write a linear equation that passes the point (2,-9) and has a slope of -5

Mathematics
2 answers:
Dimas [21]3 years ago
7 0

Answer: i want to say 13-8

Step-by-step explanation:

Nezavi [6.7K]3 years ago
3 0

Answer:

idk sorry

Step-by-step explanation:

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MissSmartiez, when you're done please answer these questions.:)
BabaBlast [244]
The first one is number 2 the second one is 185.(could you also say what is in the drop down menu for the third one. The last one is Part A is 376 and part B is 1,3,4.Hoped it helped a bit :)
7 0
3 years ago
Read 2 more answers
For which operations is the set {0, 1} closed?
velikii [3]
0 × <span>0 = 0
0 </span>× <span>1 = 0
1 </span>× <span>1 = 1

Which means multiplication is closed under {0, 1}

</span><span>1 </span>÷ <span>1 = 1
0 </span>÷ <span>1 = 0
</span>
Division is not closed under {0, 1}

1 + 1 = 2

Addition is not closed under {0, 1}

0 - 1 = -1

Subtraction is not closed under {0, 1} either



So it's only A. Multiplication which is closed under {0, 1}
5 0
3 years ago
Alexis has $22 75 to spend at the movies she buys a ticket for $8.500 a popcorn for $725 and a candy bar for $5 how much money d
vaieri [72.5K]

Answer:

  • $2.00

Step-by-step explanation:

<u>Alexis spends:</u>

  • $8.50 + $7.25 + $5 = $20.75

<u>Money left:</u>

  • $22.75 - $20.75 = $2.00
6 0
3 years ago
Read 2 more answers
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
wolverine [178]

Answer:

x^4 - 14x^2 - 40x - 75.

Step-by-step explanation:

As complex roots exist in conjugate pairs the other zero is -1 - 2i.

So in factor form we have the polynomial function:

(x - 5)(x + 3)(x - (-1 + 2i))(x - (-1 - 2i)

= (x - 5)(x + 3)( x + 1 - 2i)(x +1 + 2i)

The first 2 factors  = x^2 - 2x - 15 and

( x + 1 - 2i)(x +1 + 2i) = x^2 + x + 2ix + x + 1 + 2i - 2ix - 2i - 4 i^2

=  x^2 + 2x + 1 + 4

= x^2 + 2x + 5.

So in standard form we have:

(x^2 - 2x - 15 )(x^2 + 2x + 5)

= x^4  + 2x^3 + 5x^2 - 2x^3 - 4x^2 - 10x - 15x^2 - 30x - 75

= x^4 - 14x^2 - 40x - 75.

7 0
3 years ago
Find the gradient of the line segment between the points (0,2) and (-2,10).​
Tasya [4]

Answer:

-4

Step-by-step explanation:

Find the gradient of the line segment between the points (0,2) and (-2,10).​

Given data

x1= 0

x2= -2

y1= 2

y2=10

The expression for the gradient is given as

M= y2-y1/x2-x1

substitute

M= 10-2/-2-0

M= 8/-2

m= -4

Hence the gradient is -4

5 0
3 years ago
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